Sequence

首页 > TAG信息列表 > Sequence

LeetCode 128 Longest Consecutive Sequence

Given an unsorted array of integers nums, return the length of the longest consecutive elements sequence. You must write an algorithm that runs in \(O(n)\) time. Solution 既然不能排序，那就用 \(set\) 将元素全部存进去。从所有可能序列中的最小开始遍历，逐次递增，然后

UVM Sequence总结

一个sequence生成一系列的sequence_item，并通过sequencer发送给驱动程序，Sequence是通过扩展uvm_sequence来编写的。 uvm_sequence 派生自 uvm_sequence_item sequence用 sequence_item 的类型参数化，这定义了和 driver 之间发送/接收的 sequence_item 的类型。 sequence base clas

CF3D Least Cost Bracket Sequence 题解

CF3D 题意一个括号序列，其中有几位为 ?，将第 \(i\) 个 ? 修改为 ( 的代价是 \(a_i\)，修改为 ) 的代价是 \(b_i\)，问将所有 ? 修改后使得序列匹配的最小代价。分析贪心。发现一个匹配的括号序列的每一个前缀的左括号数一定不小于右括号数，因此先把问号都替换成右括号，对于每一位判断一

UVM TestBench

UVM 测试平台是通过扩展 uvm 类构建的。 UVM 测试平台层次结构下面是典型的 UVM 测试平台层次图。下面解释每个测试平台元素的作用， UVM test test 是最顶层的类。test负责：配置测试台。通过在层次结构中构建下一个级别来启动测试台组件构建过程，例如：env。通过启动序列来发送

基于TextCNN的文本情感分类

TextCNN 在文本处理中使用卷积神经网络:将文本序列当作一维图像一维卷积 -> 基于互相关运算的二维卷积的特例: [外链图片转存失败,源站可能有防盗链机制,建议将图片保存下来直接上传(img-8jxoMAyc-1662482583202)(../img/TextCNN-1%E7%BB%B4%E5%8D%B7%E7%A7%AF.png)] 多通道的一

【数据结构】二叉树搜索树（二叉排序树）BST专题

46. 二叉搜索树的后序遍历序列 class Solution { public: vector<int> seq; bool verifySequenceOfBST(vector<int> sequence) { seq = sequence; return dfs(0, seq.size() - 1); } bool dfs(int l, int r) { if (l >= r) r

程序报错：UnicodeDecodeError: 'gbk' codec can't decode byte 0xad in position 2: illegal mu

当我输入代码，读取文件的时候 file=open('a.txt','r') print(file.readlines()) file.close() 结果报这个错：一看，发现编码出错了，百度了一下，原来open函数其中的encoding参数的默认值是None是不能读取中文字符的，所以要给encoding参数重新传入值才能读取中文字符。修改后的代

PAT Advanced 1029 Median（25）

题目描述： Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1 = { 11, 12, 13, 14 } is 12, and the median of S2 = { 9, 10, 15, 16, 17 } is 15. The median of two sequences is defined to be

936. Stamping The Sequence

You are given two strings stamp and target. Initially, there is a string s of length target.length with all s[i] == '?'. In one turn, you can place stamp over s and replace every letter in the s with the corresponding letter from stamp. For ex

微信的消息序列号生成实践

学习一下微信是怎么搞定序列号的。从seqsvr申请的、用作数据版本号的sequence，具有两种基本的性质： 1. 递增的64位整型变量 2. 每给用户有自己独立的64位sequence 空间。（每个用户哦）具体的技术架构原型：　　不考虑seqsvr具体架构的话，它应该是一个巨大的64位数组，每个用户独占

LeetCode 127 Word Ladder

A transformation sequence from word beginWord to word endWord using a dictionary wordList is a sequence of words beginWord -> s1 -> s2 -> ... -> sk such that: Every adjacent pair of words differs by a single letter. Every si for 1 <= i <

POJ2955 Brackets

题目链接题目 Description We give the following inductive definition of a “regular brackets” sequence:the empty sequence is a regular brackets sequence,if s is a regular brackets sequence, then (s) and [s] are regular brackets sequences, andif a and b are r

POJ1458 Common Subsequence

题目链接题目 Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..., xm > another sequence Z = < z1, z2, ..., zk > is a subsequence of X if there exists a

Hibernate之Table ‘xxx.hibernate_sequence‘ doesn‘t exist异常

Hibernate之Table ‘xxx.hibernate_sequence‘ doesn‘t exist异常异常截图使用Hibernate jpa操作Mysql出现如下异常：原因分析表hiberate_sequence的作用为当主键id增长方式选择以sequence方式时，那么表hibernate_sequence用于记录其他表的主键。代码中实体注解为@GeneratedVa

ORA-00001: 违反唯一约束条件

oracle 中执行 sql 语句时，报错：“ORA-00001: 违反唯一约束条件 SYS_C00149474” --第一步：查看违反约束的序列对应的数据库表与字段 select a.constraint_name,a.constraint_type,b.column_name,b.table_name from user_constraints a inner join user_cons_columns b on a.tab

"蔚来杯"2022牛客暑期多校训练营2 K Link with Bracket Sequence I

K Link with Bracket Sequence I 题目大意：给定一个长度为\(n\)的括号序列\(a\)，\(a\)是一个长度为\(m\)的合法括号序列\(b\)的子序列，求\(b\)的方案数（\(mod\ 10^9+7,1<=n<=m<=200\) ）解题思路：考虑类似最长公共子序列的动态规划，加上括号序列需要合法的限制定义状态： \[dp[i][j][k]

"蔚来杯"2022牛客暑期多校训练营2 K-Link with Bracket Sequence I

问题描述 Link has a bracket sequence a of length n, which is a subsequence of a valid bracket sequence b of length m. Link doesn't remember b, so he wonders the number of possible sequences b. A bracket sequence is valid if it satisfies any of the follow

odoo Reloading the model registry after database signaling, pgpool, cluster

现象搭odoo集群时服务总是重新加载并提示:Reloading the model registry after database signaling 原因主从数据sequence不一致导致解决 ## 调整源码 def check_signaling(self): """ Check whether the registry has changed, and performs all necessary

Odoo 中创建序列并生成用于记录的序列值

简介总是需要自动编号的，物资要编号，档案要编号，怎么在odoo自动编号一：使用xml注册序列 data/sequence.xml 记得注册到__manifest__.py <?xml version="1.0" encoding="utf-8"?> <odoo> <data noupdate="1"> <record id="it_equipment_seq

Educational Codeforces Round 132 (Rated for Div. 2) C

https://codeforces.com/contest/1709/problem/C 题意给你一个只包含{(,),?}的字符串。问有没有可能通过把?变成(或者)，使得只存在唯一的改变方法能让字符串变为regular的 regular定义：A regular bracket sequence (or, shortly, an RBS) is a bracket sequence that can be transf

5. UVM -- suquence机制

UVM -- suquence机制 1.1. sequence 机制的原理 1.2. sequence机制的使用 1.3. sequence 的启动（2种方法） 1.3.1. 方法一：设置default_sequence 1.3.2. 方法二：手动启动sequence （更常用） task my_base_test::run_phase(uvm_phase phase); my0_seq m_seq = my0_seq::type_id:

bzoj#2656. [Zjoi2012]数列(sequence)

https://darkbzoj.cc/problem/2656 https://www.luogu.com.cn/problem/P2609 \[A[i]=A[\frac{i}{2}],2\mid i \]\[A[i]=A[\frac{i}{2}]+A[\frac{i}{2}+1],2 \not\mid i \]考虑递归转递推，这种一定能转化为 \(k_1A_0+k_2A_1\) 的形式。考虑当前有 \(ans=k_1A_i+k_2A_{i+1}\) 若 \(i

python 热力地图

from pyecharts.charts import Map from pyecharts import options as opts ##要用世界地图：maptype=“world” ##要用中国地图： maptype=“china” ##要用广东地图：maptype=“广东” value = [115.4,121.6,122,116,123.3,110.4,118.4,116.8,114.3, 113.2,111.8,116.8,113

协议通信中的asn1证书报文数据解析预研

1.首先准备ASN.1的查看工具，本例采用的是Asn1View.exe，需要自行下载。该工具可以查看base64编码后的文件，比如我们常用的x.509数字证书，p7b证书链，p12证书，pfx个人交换证书，p10证书请求文件，当然，这个工具也可以查看通讯上的asn1编码的数据，比如ldap协议通信中的asn1数据，snmp中的asn1编码的

线段树之区间更新The Child and Sequence

Description At the children's day, the child came to Picks's house, and messed his house up. Picks was angry at him. A lot of important things were lost, in particular the favorite sequence of Picks. Fortunately, Picks remembers how to repair t