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2021-07-11

if (newFunFlag) { if (currentShapeNum == 0)当前图形为I型 { int wells_a = 0,计算上面无方块的井深 holes_wells = 0,井上有无方块 wells_count = 0,井数量 wells_ab1 = 0,记录井深 row_1 = 0,行 col_1 = 0,列 holes_wells_a = 0; f

Cesium 添加 Polygon与multiPolygon

转载 Cesium 添加 Polygon与multiPolygon 为了逻辑清晰,我把代码分成了如下几部分,亲测可用 1)首先区分是polygon还是multiPolygon,若为multpolygon,则首先把multpolygon拆分为多个polygon,然后循环,把polygon字符串上球 addMultiPolygon(polygonString) { this

CF797F Mice and Holes

Link Solution 有一个非常显然的性质,一个洞最终容纳的一定是一段横坐标连续的老鼠。就是说不可能出现交叉的请况。数学证明也是非常的容易,懒得写了。 那么就预先将老鼠和洞分别按横坐标排序。这样之后,容易想到 dp 状态 \(dp[i][j]\) 表示用前 \(i\) 个洞容纳前 \(j\) 个老鼠的最小

[2020CCPC威海B] Labyrinth - 结论,BFS

Description 给定一张 \(n \times m\) 的棋盘,上面有 \(k\) 个障碍物,有 \(q\) 次询问,每次给定两个点 \((x_1,y_1),\ (x_2,y_2)\),问这两点之间的最短路径长度。\(n\cdot m \le 2 \times 10^5, k \le 42, q \le 10^5\) Solution 对于 \((x_1,y_1),\ (x_2,y_2)\) 两点构成的最短路径,如

「Codeforces 13E」Holes

Description Hint \(1\le N, M\le 10^5\) Solution 我们将 \(n\) 个位置以及弹出看作 \(n + 1\) 个点,将弹力视作连边。 考虑 Link-Cut Tree。 操作 0 a b:cut 原来的连边,link 新边。 操作 1 a:split(a, n + 1),然后跳的次数就是 size[n + 1] - 1。 但是最后的位置怎么求?这个简单,只要

HDU ACM Steps:Wolf and Rabbit

HDU ACM Steps:Wolf and Rabbit 题目描述 There is a hill with n holes around. The holes are signed from 0 to n-1. A rabbit must hide in one of the holes. A wolf searches the rabbit in anticlockwise order. The first hole he get into is the one signed with

E - Holes

题目链接:http://codeforces.com/problemset/problem/13/E Little Petya likes to play a lot. Most of all he likes to play a game «Holes». This is a game for one person with following rules: There are N holes located in a single row and numbered from left to ri

HDU1222 FLY

Problem Description There is a hill with n holes around. The holes are signed from 0 to n-1. A rabbit must hide in one of the holes. A wolf searches the rabbit in anticlockwise order. The first hole he get into is the one signed with 0. Then he will ge

WebGL之构建导洞多边形

nannan 岛洞多边形是一种复杂几何对象类型。SuperMap iDesktop中的定义是:在可编辑状态下,将两个或两个以上具有包含关系的面对象在重合区域进行处理(删除或者保留,面对象为偶数则重合部分将删除,为奇数则保留),最终形成一个岛洞多边形。如一个区域内有湖泊时,就会得到一个岛洞多