2021-07-11
作者:互联网
if (newFunFlag) {
if (currentShapeNum == 0)当前图形为I型
{
int wells_a = 0,计算上面无方块的井深
holes_wells = 0,井上有无方块
wells_count = 0,井数量
wells_ab1 = 0,记录井深
row_1 = 0,行
col_1 = 0,列
holes_wells_a = 0;
for (int j = 0; j < STAGE_WIDTH; j++)
{
for (int i = STAGE_HEIGHT-1; i >=0; i--)
{
if (Field[i][j] == 0)
{
if ((j - 1 < 0 || Field[i][j - 1] > 0) && (j + 1 >= STAGE_WIDTH || Field[i][j + 1] > 0))
{//两边是墙或者实心方格
wells_a++;
}
if (Field[i - 1][j])井上有方块
holes_wells++;
}
if (((holes_wells == 0) && ((wells_a == 3) || (wells_a == 4)))&& ((j - 1 < 0 || Field[i][j - 1] > 0) && (j + 1 >= STAGE_WIDTH || Field[i][j + 1] > 0)))test
{
wells_ab1 = wells_a;
holes_wells_a = holes_wells;
row_1 = i;
col_1 = j;
}
if (((holes_wells_a == 0) &&((wells_ab1==3)|| (wells_ab1 == 4)))&&((j - 1 < 0 || Field[i][j - 1] > 0) && (j + 1 >= STAGE_WIDTH || Field[i][j + 1] > 0)))有上面无方块的井-》下落插入井
{
wells_count++;
}
}
wells_a = 0;
holes_wells = 0;
}
if (wells_count)有井,插入√
{
for (int t = 0; t < 4; t++)
currentSquare[t].x = currentSquare[t].x -STAGE_WIDTH/2+ col_1-1;如果有几个3或4深度井,直接移到最右的井上
}
else无井->放到hold区
{
if (hold_count == 0)hold区无方块
{
holdFunc();
hold_count = 1;
goto aa;
}
else√
{
if(holdShapeNum!=0)
holdFunc();
}
}
}
else当前方块为其他方块
{
aa:
int wells_a = 0,计算上面无方块的井深
wells_count = 0,
holes_wells = 0,
temp = 0,
wells_ab2 = 0,
row_2,行
col_2,列
holes_wells_b=0;
for (int j = 0; j < STAGE_WIDTH; j++)
{
for (int i = STAGE_HEIGHT - 1; i >=0; i--)
{
if (Field[i][j] == 0)
{
if ((j - 1 < 0 || Field[i][j - 1] > 0) && (j + 1 >= STAGE_WIDTH || Field[i][j + 1] > 0))
{//两边是墙或者实心方格
wells_a++;
}
if (Field[i - 1][j])井上有方块
holes_wells++;
}
if ((((wells_a == 3) || (wells_a == 4))&&(holes_wells==0))&& ((j - 1 < 0 || Field[i][j - 1] > 0) && (j + 1 >= STAGE_WIDTH || Field[i][j + 1] > 0)))///test
{
wells_ab2 = wells_a;
holes_wells_b = holes_wells;
row_2 = i;
col_2 = j;
}
if (((holes_wells_b == 0) && ((wells_ab2 == 3) || (wells_ab2 == 4)))&& ((j - 1 < 0 || Field[i][j - 1] > 0) && (j + 1 >= STAGE_WIDTH || Field[i][j + 1] > 0)))有上面无方块的井-》下落插入井
{
wells_count++;
}
}
wells_a = 0;
holes_wells = 0;
}
if (wells_count)√
{
if (hold_count)hold有图形
if (holdShapeNum == 0)I型图形
holdFunc();将I型换出来插入井
}
}
if (newFunFlag)
{
PierreDellacherie();
for (int j = 0; j < tPD.r; j++) {
AIRotateFunc();
}
for (int i = 0; i < 4; i++) {
currentSquare[i].x += tPD.x;
}
newFunFlag = false;
}
}
标签:11,07,++,holes,wells,Field,2021,&&,STAGE 来源: https://blog.csdn.net/qq_41994314/article/details/118650819