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Leetcdoe 2037. 使每位学生都有座位的最少移动次数（可以,一次过）

一个房间里有 n 个座位和 n 名学生，房间用一个数轴表示。给你一个长度为 n 的数组 seats ，其中 seats[i] 是第 i 个座位的位置。同时给你一个长度为 n 的数组 students ，其中 students[j] 是第 j 位学生的位置。你可以执行以下操作任意次：增加或者减少第 i 位学生的位置，每次变化量

Python实现电影订票系统

一、前言大家都喜欢看电影吧，一部新剧上场的时候往往会抢不到票，今天通过Python实现一个电影订票系统，满足你想看电影的心。二、整体结构图三、代码分解 3.1 infos.py 一部电影的详细信息适合用字典结构来存储，我们可以给字典里添加多个键值对来保存电影的名称

Leetcode1349:参加考试的最大学生数（动态规划+状态压缩+位运算）

Given a m * n matrix seats that represent seats distributions in a classroom. If a seat is broken, it is denoted by '#' character otherwise it is denoted by a '.' character. Students can see the answers of those sitting next to the lef

audio, audience, auditorium

audio-1. relating to hearing or sound2. relating to sound that is recorded or broadcast A sound that is audible is loud enough to be heard. ≠inaudible 副词: audibly; 名词:audibility audience的词源是hearing. A studio audience is a group of people who are in a

第十二篇英语翻译

出处：https://acs.jxnu.edu.cn/contest/23/board/challenge/B； Not Sitting 描述： Rahul and Tina are looking forward to starting their new year at college. As they enter their new classroom, they observe the seats of students are arranged in a n×mn×m grid. T

849. 到最近的人的最大距离

给你一个数组 seats 表示一排座位，其中 seats[i] = 1 代表有人坐在第 i 个座位上，seats[i] = 0 代表座位 i 上是空的（下标从 0 开始）。至少有一个空座位，且至少有一人已经坐在座位上。亚历克斯希望坐在一个能够使他与离他最近的人之间的距离达到最大化的座位上。返回他到离他最近的

5885. 使每位学生都有座位的最少移动次数

力扣打卡：5885. 使每位学生都有座位的最少移动次数解题思路题目的意思：找到两个数组的任意两个数差的绝对值的和的最小值也就是数组中最大的和最大的比，次大的和次大的比。。最小的和最小的进行比较代码 class Solution { public int minMovesToSeat(int[] seats, int[]

20个原生jsdemo：2 movie-seat-booking

HTML movie 电影数据 container 座位容器，用来提交座位数据 seats 座位数据 count total 通过select标签选择电影数据；通过给座位div设计点击事件，来更新座位的数据，然后返回相应的count与total在页面上 CSS 主要需要修改点击后的seats主题 JS 1 populiateUI()//初始化界面将座

D2. Seating Arrangements (hard version)

题目： It is the hard version of the problem. The only difference is that in this version 1≤n≤300 In the cinema seats can be represented as the table with n rows and m columns. The rows are numbered with integers from 1 to n. The seats in each row are nu

实训三#3.9占位置

[problem description] the classroom seats in sun's school can be reserved every day. A person can occupy multiple seats and must have consecutive seats. If he can't occupy so many seats he requires, he won't want any more. In order to reduc

[LeetCode] 849. Maximize Distance to Closest Person_Medium tag: BFS, array

You are given an array representing a row of seats where seats[i] = 1 represents a person sitting in the ith seat, and seats[i] = 0 represents that the ith seat is empty (0-indexed). There is at least one empty seat, and at least one person sitting

2021-07-08

You are a movie theater manager. You are given a two-dimensional array with 6 rows and 6 columns - 36 elements with 0 value, that represent empty theater seats. All 36 tickets for session were sold, so you need to identify all of the seats with value 1.

6.18Java多线程并发、同步练习DemoNo1

6.18Java多线程并发、同步练习DemoNo1 不和选择的线程数据安全 package iostudy.synchro;/** * 多线程模拟影院选位置 * @since JDK 1.8 * @date 2021/6/18 * @author Lucifer */public class HappyCinema { public static void main(String[] args) { /*实例

差分数组+LeetCode1109

差分数组定义性质及用途 1.定义对于一个长度大小为n的数组arr[n] 我们可以建立他的差分数组f[n]。其中f[i] = arr[i] - arr[i-1]。例如 f[2] = arr[2] - arr[1]。 2.性质 (1) 可通过差分数组计算arr[i]的值： arr[i] = f[i] + f[i-1] + ... + f[0] 或 arr[i] = f[i] + ar

[LeetCode] 1845. Seat Reservation Manager

Design a system that manages the reservation state of n seats that are numbered from 1 to n. Implement the SeatManager class: SeatManager(int n) Initializes a SeatManager object that will manage n seats numbered from 1 to n. All seats are init

操作系统习题1

某银行提供1个服务窗口和10个供顾客等待的座位。顾客到达银行时，若有空座位，则到取号机上领取一个号，等待叫号。取号机每次仅允许一位顾客使用。当营业员空闲时，通过叫号选取一位顾客，并为其服务。顾客和营业员的活动过程描述如下： //首项应该定义信号量 semaphore mutex=1,seats=1

849. Maximize Distance to Closest Person

You are given an array representing a row of seats where seats[i] = 1 represents a person sitting in the ith seat, and seats[i] = 0 represents that the ith seat is empty (0-indexed). There is at least one empty seat, and at least one person sitting

0849. Maximize Distance to Closest Person (M)

Maximize Distance to Closest Person (M) 题目 You are given an array representing a row of seats where seats[i] = 1 represents a person sitting in the ith seat, and seats[i] = 0 represents that the ith seat is empty (0-indexed). There is at least one empty s

大挑战！状压dp！

1349. 参加考试的最大学生数给你一个 m * n 的矩阵 seats 表示教室中的座位分布。如果座位是坏的（不可用），就用 '#' 表示；否则，用 '.' 表示。学生可以看到左侧、右侧、左上、右上这四个方向上紧邻他的学生的答卷，但是看不到直接坐在他前面或者后面的学生的答卷。请你计算并返

849. 到最近的人的最大距离

思路： 1、找到seats中第一、最后一个1的位置，分别为：low、high；2、求得最后一个1的后面1的个数recindex（因为要坐最后那么所隔距离就为recindex）；3、遍历seats从low到high的元素，用res[]存放每一段连续的0的个数；4、求得res中的最大值leng，通过leng的奇偶求得最远

odoo 计算字段和默认值

计算字段如下 import randomfrom odoo import models, fieldsclass ComputedModel(models.Model): _name = 'test.computed' name = fields.Char(compute='_compute_name') @api.multi def _compute_name(self): for record in self:

java 多线程-快乐订座电影院

原文链接：https://blog.51cto.com/14437184/2429533 java 多线程-快乐订座电影院 public class test{ public static void main(String[]args) { //可用位置 List available =new ArrayList(); available.add(1); available.add(2); available.add(3);

Akka的事务STM

一个事务必须具有以下四个特点，即所谓的ACID特性：原子性：所有的操作要么全部成功，要么全部失败。一致性：在事务完成后，系统保持一致性状态。隔离性：在一个事务成功或失败前，产生的数据对于系统中的其他事务是不见的。持久性：事务操作的结果要持久化保存。 Akka使用（Software Tra

技术博客03 软件需求工程和UML建模第二组

UML建模结构化需求分析第二组校车座位预约系统 01 结构化需求分析概述功能分解图：需求优先级划分：需求细化： 02 过程建模数据流图DFD片段：数据流图DFD-0层：数据流图DFD-1层：微规格说明（伪码）： Read the