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ansible使用报错not possible

一、问题描述: 执行ansible webservers -m ping报错如下(hosts文件指定ssh_user,ssh_pass) 二、解决方案 vim /etc/ansible/ansible.cfg 修改配置文件中的 host_key_checking = False 修改并发数 forks=8

pycharm拉取git报错“WARNING: POSSIBLE DNS SPOOFING DETECTED!”

【现象】 @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@ @ WARNING: POSSIBLE DNS SPOOFING DETECTED! @ @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@ The ECDSA host key for gitlab.xxx.com has changed, and the key for the corresponding

sap 登陆不可能(许可协议检查出错)Logon not possible (error in license check)

背景: 证书过期或是克隆完应用首次登录的报错 这个时候可以用sap*用户登录000client。 tcode>slicense 检查然后上传许可。 申请一个licence或是在sap的许可网站找到已经申请过的许可刷新下载。 ‘https://websmp101.sap-ag.de/licensekey ’

1.26号英语翻译

题目来源:http://noi.openjudge.cn/ch0205/1253/ 重点词汇: Dungeon:n.地牢; compose: v.组成; letter :n.字母,信; character:n.字符,人物,性格; terminate:adj.临界的,有限的; 1253:Dungeon Master   地下城主 查看 提交 统计 提问 总时间限制: 1000ms 内存限制: 65536kB描述You are

WARNING: POSSIBLE DNS SPOOFING DETECTED 错误解决办法

原本一切都好好的, 突然有一天用 git push 报错如下: WARNING: POSSIBLE DNS SPOOFING DETECTED! 上述错误一般是公司的 Git 仓库迁移了导致 ip 发生变化, git 的目录下有个known_hosts文件存储了连接过的域名以及对应的 ip, 每次有远程操作的时候都会验证里面的信息是否匹配, 仓

Django设计哲学

https://docs.djangoproject.com/en/3.2/misc/design-philosophies/#cache-design-philosophy Loose coupling 低耦合 高内聚-低耦合是其设计目标。 不同的层不需要知道其它层, 除非是绝对必要。 例如: 模板系统不用知道请求 数据库层不用知道数据显示 视图系统不关心模板系统   尽

swagger Failed to fetch. Possible Reasons:CORS

使用gin-swagger出现Failed to fetch. Possible Reasons:CORS Network Failure URL scheme must be “http” or “https” for CORS request 解决方案 原因:跨域问题导致 解决方法: 添加Cors中间件,代码如下 func Cors() gin.HandlerFunc { return func(c *gin.Context) { m

函数总结(1)

1、rcu_read_lock() 背景:CPU的速度与访问内存的速度差距越来越大,而这种锁使用了原子操作指令,它需要原子地访问内存,也就说获得锁的开销与访存速度相关。 RCU(Read-Copy Update),是 Linux 中比较重要的一种同步机制。顾名思义就是“读,拷贝更新”,再直白点是“随意读,但更新数据的

Colormap Possible values

Possible values are: Accent, Accent_r, Blues, Blues_r, BrBG, BrBG_r, BuGn, BuGn_r, BuPu, BuPu_r, CMRmap, CMRmap_r, Dark2, Dark2_r, GnBu, GnBu_r, Greens, Greens_r, Greys, Greys_r, OrRd, OrRd_r, Oranges, Oranges_r, PRGn, PRGn_r, Paired, Paired_r, Pastel1, P

886. Possible Bipartition

Given a set of n people (numbered 1, 2, ..., n), we would like to split everyone into two groups of any size. Each person may dislike some other people, and they should not go into the same group.  Formally, if dislikes[i] = [a, b], it means it is not

Aladdin and the Flying Carpet

Aladdin and the Flying Carpet(素数打表+唯一分解定理) It’s said that Aladdin had to solve seven mysteries before getting the Magical Lamp which summons a powerful Genie. Here we are concerned about the first mystery. Aladdin was about to enter to a magical

POJ-2251 Dungeon Master(三维搜索bfs)

Dungeon Master Time Limit: 1000MS Memory Limit: 65536K 题目链接http://poj.org/problem?id=2251 Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. I

Codeforces Round #715 (Div. 2) C. The Sports Festival(dp)

Assume that the array of speeds is sorted, i.e.

IPFS (2) 系统技术架构

1. 模块组成 2. Storing content in IPFS 3. Data sharing on IPFS by owner 【参考】 [1] "5G, Blockchain and IPFS: A General Survey with Possible Innovative Applications in Industry 4. "

歌曲:Gravity It Possible

OIerSuperTer理科原创翻唱歌曲 I will study, I will try, I will search. 我要学习,我要尝试,我要探索。 I enjoy it, oh. 哦,我乐在其中。 Speed up, to the Escape velocity, 加速,加速到第二宇宙速度, escape the planet. 便能逃离星球。 Oh, the gravity is laws of nature, and we

Leetcode 767. Reorganize String

Description: Given a string S, check if the letters can be rearranged so that two characters that are adjacent to each other are not the same. If possible, output any possible result.  If not possible, return the empty string. Link: 767. Reorganize String

open

we need to open ourselves as much as possible it is the only approach where we can enhance our abilities for a better life!

Grazing2 S(DP)

原题: Grazing2 S 时间限制: 1 Sec  内存限制: 125 MB 题目描述 Farmer John has N (2 <= N <= 1,500) prize milk cows conveniently numbered 1..N. His newly-painted barn has S (N <= S <= 1,000,000) stalls (conveniently numbered 1..S) in a single long line; ea

MySql中explain之possible_keys、key及key_len介绍

MySql中explain之possible_keys、key及key_len介绍 possible_keys: 显示可能应用在这张表中的索引,一个或多个。 查询涉及到的字段上若存在索引,则该索引将被列出,但不一定被查询实际使用 key: 实际使用的索引。如果为NULL,则没有使用索引 查询中若使用了覆盖索引,则该索引和查

875. 爱吃香蕉的珂珂

875. 爱吃香蕉的珂珂 题目链接:875. 爱吃香蕉的珂珂 珂珂喜欢吃香蕉。这里有 N 堆香蕉,第 i 堆中有 piles[i] 根香蕉。警卫已经离开了,将在 H 小时后回来。 珂珂可以决定她吃香蕉的速度 K (单位:根/小时)。每个小时,她将会选择一堆香蕉,从中吃掉 K 根。如果这堆香蕉少于 K 根,她将吃掉这堆

screen

screen 新建一个屏幕:screen -S name ./frp 启动一个名字为name的screen; 枚举所有的屏幕:screen -ls 是列出所有的screen; 跳转到某一个屏幕:screen -r name或者id,就可以回到某个screen了; 切换到上一个屏幕:ctrl + a + d 可以回到前一个screen,当时在当前screen运行的程序不会停

Codeforces Round #676 (Div. 2)A. XORwice,水题

problem A. XORwice time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output In order to celebrate Twice’s 5th anniversary, Tzuyu and Sana decided to play a game. Tzuyu gave Sana two integers a and b and a

LeetCode 886. Possible Bipartition?

Given a set of N people (numbered 1, 2, …, N), we would like to split everyone into two groups of any size. Each person may dislike some other people, and they should not go into the same group. Formally, if dislikes[i] = [a, b], it means it is not allo

1162. As Far from Land as Possible

package LeetCode_1162 import java.util.* /** * 1162. As Far from Land as Possible * https://leetcode.com/problems/as-far-from-land-as-possible/ * Given an n x n grid containing only values 0 and 1, where 0 represents water and 1 represents land, * f

没用 Java 8,怎么优雅地避免空指针?

JDK 8 里面有Optional,如果你还在使用 JDK 7 及之前的版本,那么可以使用 Google 的 Guava 库,用法差不多,下面介绍一下Google 的 Guava 库用法。为什么使用 Google Guava Optional 使用Optional除了简化粗鲁的if(null == object)、降低函数的复杂度、增加可读性之外,它是一种傻瓜式的