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1151 LCA in a Binary Tree (30 分)（树的遍历，LCA算法）
The lowest common ancestor (LCA) of two nodes U and V in a tree is the deepest node that has both U and V as descendants. Given any two nodes in a binary tree, you are supposed to find their LCA. Input Specification: Each input file contains one test case【PAT】1020 Tree Traversals (25 分)
#include <iostream> #include <vector> #include <queue> using namespace std; struct node { int data; int lchild,rchild; }; vector<int> post,in; vector<node> T; int t_index=0; int lca(int inl,int inr,int postRoot){PAT刷题之旅 1151-LCA in a Binary Tree-甲级
题目 The lowest common ancestor (LCA) of two nodes U and V in a tree is the deepest node that has both U and V as descendants. Given any two nodes in a binary tree, you are supposed to find their LCA. Input Specification: Each input file contains one tes1151 LCA in a Binary Tree（两结点的最近公共祖先）
大致题意就是给出一棵树的先序、中序遍历序列，可以构造一棵树。然后给两个顶点，找出这两个结点的最近公共祖先。 1 #include<iostream> 2 #include<unordered_map> 3 #include<algorithm> 4 using namespace std; 5 const int maxn = 10010; 6 int m,n,pre[maxn],in[maxn],Java解决重建二叉树算法题
题目描述 输入某二叉树的前序遍历和中序遍历的结果，请重建出该二叉树。假设输入的前序遍历和中序遍历的结果中都不含重复的数字。例如输入前序遍历序列{1,2,4,7,3,5,6,8}和中序遍历序列{4,7,2,1,5,3,8,6}，则重建二叉树并返回。 解题思路 由二叉树的前序遍历序列可知，1 为二叉最低公共祖先（LCA）
对于一颗给定的二叉树，对任意两个节点，求它们的最低的公共祖先。 下面就是这样一道题，给定一棵树的前序和中序遍历（我们知道这颗树就是确定的了），对于任两个节点，求它们的最低公共主祖先。 1151 LCA in a Binary Tree （30 分） #include<iostream> #include<cstdio> #include<map> using name