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A comb is a tool consisting of a shaft [长柄] that holds a row of teeth for pulling through the hair to clean, untangle, or style it. Combs have been used since prehistoric times, having been discovered in very refined forms from settlements dating back to【poj 3250】Bad Hair Day 单调栈/ST表
题目 给你n头牛的身高,\(c_i=\)[i+1,n]中比第i头牛高度矮的牛的数目 注意,如果\(h_j\)比\(h_{j+1}\)高,那么第j头牛是会把j+1头挡住的 求\(\sum_i{c_i}\) n<=80000 方法1:ST表 从一个最朴素的想法而来——对于第i头牛,我们需要找出[i+1,n]中第一个比\(h_i\)高的位置j,然后ans+=j-i-1; 如洛谷P2866 [USACO06NOV]Bad Hair Day S (单调栈)
看到这道题很容易想到单调栈,但我一开始想的是从后往前扫,但发现会有问题(因为这样会对后面牛的答案造成影响),所以这时我们要及时换一个思路,从前往后扫。 维护一个单调递减的栈,插入h[i]时,小等于它的数都要出栈,累加栈中元素数量,表示的意义就是:当前栈中的牛都是可以看到i这头牛的,即他们【团队介绍】头发茂盛队 hair duang duang | week6
项目 内容 这个作业属于哪个课程 2022春季软件工程(罗杰 任健) 这个作业的要求在哪里 团队项目-团队介绍 一、队名 头发茂盛队 | hair duang~ duang~ 以一票之差获得胜利的队名 蕴含了广大程序猿群体对于发量的殷切期盼 二、团队成员 姓名 真相 个人介绍 PM 前端开barber
A barber is a person whose occupation is mainly to cut, dress, groom, style and shave men's and boys' hair or beards. A barber's place of work is known as a "barbershop" or a "barber's". In previous times, barbers (【Luogu P2866】[USACO06NOV]Bad Hair Day S
[USACO06NOV]Bad Hair Day S 洛谷题面 题目大意: 给定有 \(n\) 个数的数组 \(a_i\),找到在 \(i\) 之后的第一个大于 \(a_i\) 的数 \(a_j\),那么 \(a_i\) 能造成 \(j-i\) 贡献。求总贡献。 思路: 倒着跑单调栈。 代码: const int N = 8e4 + 10; inline ll Read() { ll x = 0, f = 1;vue3 setup reactive响应数据
reactive不能修饰基本数据类型只能修饰对像和数组 改变对象(可以该变更深层次的对象) <template> 名字:{{name}} <br> 年龄:{{age}} <br> 性别:{{obj.sex}} <br> 身高:{{obj.long}} <br> 发行:{{obj.hair.color}}和{{obj.hair.type}} <br> <button @click="growup()"单词.人体
部分 原形 复数 头 head heads 头发 hair hair 额头 forehead foreheads 眉毛 eyebrow eyebrows 眼睛 eye eyes 耳朵 ear ears 鼻子 nose noses 脸 face faces 嘴巴 mouth mouths 下巴 chin chins 脖子 neck necks 胳膊 arm arms 手 hand hands基于MeSC与交感神经作用关系的压力水平与白发模拟系统和压力规划系统(Matlab)
基于MeSC与交感神经作用关系的压力水平与白发模拟系统和压力规划系统 一个本人的Matlab项目,可用于根据压力水平模拟白发水平,并根据工作情况给出白发量最少的合理的压力规划。 % 细胞仿真 clc; clear; % Raw data sl0 = [0 1 2 3 4];Pyhon 爬虫框架 looter
知名的pyspider,scrapy就不说了,今天说说这个 looter。 安装 先安装好python3,需要3.6以上,然后执行 pip install looter λ looter -hLooter, a python package designed for web crawler lovers :)Author: alphardex QQ:2582347430If any suggestion, please contact me.Thank yo十六、陈述段
1、我明天还得赶飞机,6点就得起来,我得走了,如果你有什么需要,给tom打电话就行 I need to catch the airplane,I have to get up at 6 O’clock,I need to go,If you had some requirements,you could call Tom 2、你什么都不用说了,我已经告诉过你了,关于这件事我什么都不知道,你还是去Python爬虫进阶必备 | XX读书window.__DATA加密分析
今日网站: aHR0cHM6Ly9zZWFyY2guZG91YmFuLmNvbS9ib29rL3N1YmplY3Rfc2VhcmNoP3NlYXJjaF90ZXh0PSVFNCVCOCU5QyVFOSU4NyU4RSVFNSU5QyVBRCVFNSU5MCVCRSZjYXQ9MTAwMQ== 抓包与定位加密位置 上面就是这次需要分析的网站了,先简单看看抓包的结果。【图1-1】 图1-1 抓包很清楚没什么幺蛾子,【算法】POJ 3250 Bad Hair Day
解题思路 将每头牛加入单调栈,记录每次pop操作后栈的长度,也就是每头牛能被多少牛看到,累加之后与每头牛能看到的牛的数量之和一致。 题目里\(1<=n<=80,000\),如果牛的身高序列单调递减,结果最大为\(79999+79998+...+1=79999*80000/2\approx 3.2*10^9\),超出了int的范围,需要用long longA - Bad Hair Day 单调栈
题意 给你n头牛的高度,每头牛朝向右方,只能看见小于自己高度的牛,当有一头牛的高度大于等于自己时包括这头牛之后的牛也看不见。求所以牛能看见牛数量的总和。 思路 问题可以转化为每头牛被看到的牛的数量的总和,我们可以维护一个单调递增栈,当一个元素x即将入栈时,栈内元素个数202000302英语上课笔记-describe a person
Shaun (from England) [ ʃ ɔ: n ] Ada - Ruby - Cady height - hair colour - clothes trousers a tall, short, average height man/woman dark brown, brown, light/fair, mousey, blonde, ginger/red hair, grey(ing), silver, white, black + hair style (strai用人话概况Python基础(四):字典 干货来了!!!
用人话概况Python基础(四):字典 字典定义 定义:在Python中字典是一系列键-值对,每个键都会与一个值相关联。 在Python中,字典将一系列得键-值对放在花括号中,在字典中想存储多少个键-值对都可以,键-值对之间用逗号隔开 people = {‘name’:“xiaowang”,‘age’:18,‘points’:85} 字典tressfx hair
自古以来,人类头发的实时精确渲染都是游戏里最为复杂、最具挑战性的项目——成千上万、各自独立的微小细丝都是半透明的,都有复杂的阴影,还需要抗锯齿,而且为了配合人物动作,这些计算都需要每秒钟进行几十次,这对GPU来说是无比巨大的压力。 GPU厂商也在为实现更真实的头发效果而不单调栈-牛客 25084 Bad Hair Day
牛客 20806 题目意思 牛1向右看,看得见 牛2,3,4, 看不见 牛5 以及 牛5之后的牛。 求每个牛能看见牛的个数。 1 2 3 4 5 6 O O OO O OOO O OOOOOO 题解:维护一个单调递减栈,只要求每个最大值的右区间即可)。 #include <cstdio> #include <iostream> #include <stack> typedef lon洛谷 P2866 [USACO06NOV]糟糕的一天Bad Hair Day 牛客假日团队赛5 A (单调栈)
链接:https://ac.nowcoder.com/acm/contest/984/A 来源:牛客网 题目描述 Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self-conscious about her messy hairstyle, FJ wants to count the number of other cows that can see theHot celebrity hairstyles Diego Diego infighting in mind
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Cannes hair red, black list to see the celebrity hair PK Lead: the stars have exclusive ghd hair stylist, stunning high style budget, and countless modeling sponsorship, all onto the red carpet that moment must have the United States and the United States并发编程情况下几个相应问题简介
1.并发编程的挑战之死锁 死锁是两个或更多线程阻塞着等待其它处于死锁状态的线程所持有的锁。死锁通常发生在多个线程同时但以不同的顺序请求同一组锁的时候。 例如,如果线程1锁住了A,然后尝试对B进行加锁,同时线程2已经锁住了B,接着尝试对A进行加锁,这时死锁就发生了。线程1永远得不