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E. Bring Balance (括号匹配问题+贪心+前缀和)(CF 794 d2)
E. Bring Balance time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output Alina has a bracket sequence s of length 2n, consisting of n opening brackets '(' and n closing brackets ')'. AsPOJ 3264 Balanced Lineup
题目传送门 树状数组求最大最小值,一次成型,不能跑两回啊! #include <iostream> #include <string.h> #include <stdio.h> #include <vector> #include <map> #include <queue> #include <algorithm> #include <math.h> #include <cstdio> usingB. A Perfectly Balanced String?
题目链接 B. A Perfectly Balanced String? 给出一个字符串 \(s\) ,对于 \(s\) 中出现过的任意两个字母 \(u, v\) ,定义一个 Balanced 的字符串满足在任何 一个子串中 \(u\) 和 \(v\) 的出现次数相差不超过 1 . 判断字符串是否满足 Balanced 条件. 解题思路 思维 满足条件的字符串LeetCode 1541. Minimum Insertions to Balance a Parentheses String
原题链接在这里:https://leetcode.com/problems/minimum-insertions-to-balance-a-parentheses-string/ 题目: Given a parentheses string s containing only the characters '(' and ')'. A parentheses string is balanced if: Any left parenthesis '(LeetCode 1963. Minimum Number of Swaps to Make the String Balanced
原题链接在这里:https://leetcode.com/problems/minimum-number-of-swaps-to-make-the-string-balanced/ 题目: You are given a 0-indexed string s of even length n. The string consists of exactly n / 2 opening brackets '[' and n / 2 closing brackets ']'POJ 3264 Balanced Lineup
题目传送门 本题调试过程中,出现了奇怪的问题: \(G++\) \(AC\) ,\(C++\) \(Complie\) \(Error\) 以后调用\(POJ\),还是老实的\(G++\)吧~ //#include <bits/stdc++.h> #include <iostream> #include <string.h> #include <stdio.h> #include <vector> #include &洛谷P2880 [USACO07JAN] Balanced Lineup G(树状数组/线段树)
维护区间最值的模板题。 1.树状数组 1 #include<bits/stdc++.h> 2 //树状数组做法 3 using namespace std; 4 const int N=5e4+10; 5 int m,ma[N],mi[N],n,c[N]; 6 7 int lowbit(int x){ 8 return x&(-x); 9 } 10 11 void ins(int x,int v){ 12 while(x<=n){Balanced Lineup
题目链接:https://www.luogu.com.cn/problem/P2880 1 #include<cstdio> 2 #include<cmath> 3 #include<algorithm> 4 using namespace std; 5 const int maxn=5e4+10; 6 int n, q, h[maxn]; 7 int a, b; 8 int f[maxn][21], g[maxn][21]; 9 int maxh,POJ 3264 Balanced Lineup
题目链接:POJ 3264 Balanced Lineup 题目大意: 题解: ST表模板。 #include <cstdio> #include <cstring> #include <iostream> using namespace std; int num[50005], minn[50005][50], maxn[50005][50], n, q; void stPreWork() { for (int i = 1; i <= n; ++iC. Balanced Stone Heaps
https://codeforces.com/problemset/problem/1623/C 题意:有n堆石子,第i堆石子有hi个石子,你可以从第3堆开始到第n堆,将d个石子移动到i - 1堆和2d个石子移动到i - 2堆,问最后最大的最小堆为多少。 题解:二分!!!(代码有说明!) #include<iostream> #include<algorithm> #include<cstring> #[LeetCode] 110. Balanced Binary Tree
Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as: a binary tree in which the left and right subtrees of every node differ in height by no more than 1. Example1: Input: root = [3,9,20,nuP2880 [USACO07JAN]平衡的阵容Balanced Lineup 题解
瞎扯 刚看到这个题目的时候我就吓着了:蓝题?溜了溜了……但是还是好奇地点进去看了一下。看完题面之后,恕我冒昧说一句话,这题不应该是黄题吗?怎么会是蓝题?简直就是明显(luo)到不能再明显(luo)的RMQ问题。 正题 所谓RMQ问题,就是找一个序列某段区间当中,最大或最小的数是多少。而解决它的一种题解 - CF 873B. Balanced Substring
873B. Balanced Substring 思路 设'1' = '1' , '0' = '-1', 用sum记录前缀和,用pos数组记录a数组中前缀和等于k的第一个位置,因为前缀和表示1和0的个数差,当sum[a] == sum[b], (a,b]中的0和1的个数一定相同。 代码 #include <stdio.h> #include <string.h> #include <algoritCF1569A Balanced Substring 题解
题目传送门 题意 给出 \(T\) 个长度为 \(n\) 且仅含 \(\texttt{a}\) , \(\texttt{b}\) 的字符串,对于每个字符串,输出任意的 \(l\) ,\(r\) ,表示字符串的第 \(l\) 个字符到第 \(r\) 中 \(\texttt{a}\) , \(\texttt{b}\) 字符的数量相同。 \(\texttt{SOLUTION}\) 记字符串为 \(s\) ,字符串Direct Measure Matching for Crowd Counting
Direct Measure Matching for Crowd Counting IJCAI 2021 motivation 传统高斯处理办法因为高斯核会产生误差,影响精度 Idea 提出了一种新的基于度量的计数方法,将预测的密度图直接回归到散点标注的地面真实值。 人群计数是一个度量匹配问题。我们推导了一种半平衡形式的Sin[LeetCode] 1234. Replace the Substring for Balanced String 替换子串得到平衡字符串
You are given a string containing only 4 kinds of characters 'Q', 'W', 'E' and 'R'. A string is said to be balancedif each of its characters appears n/4 times where n is the length of the string. Return the minimum[LeetCode] 1221. Split a String in Balanced Strings 分割平衡字符串
Balanced strings are those that have an equal quantity of 'L' and 'R' characters. Given a balanced string s, split it in the maximum amount of balanced strings. Return the maximum amount of split balanced strings. Example 1: Input: s =使用栈进行简单括号匹配
''' 栈 实现语言: Python 有次序的数据集, 每个数据仅从栈顶一端加入和从数据集中移除 ''' class Stack: def __init__(self): self.items = [] def isEmpty(self): return self.items == [] # 入栈 def push(self, item): self.items1221. Split a String in Balanced Strings
题目: Balanced strings are those that have an equal quantity of 'L' and 'R' characters. Given a balanced string s, split it in the maximum amount of balanced strings. Return the maximum amount of split balanced strings. Example 1: InputBalanced Binary Tree
Code link: https://leetcode.com/problems/balanced-binary-tree/ Constraint: The number of nodes in the tree is in the range [0, 5000]. This means we can use recursion? Idea: Note the definition of height and depth might be differnt from the official defi14.3 balance_pgdat函数
balance_pgdat()函数是回收页面的主函数。这个函数比较长,首先看一个框架,主体函数是一个很长的while循环。 代码如下: /* * For kswapd, balance_pgdat() will work across all this node's zones until * they are all at high_wmark_pages(zone). * * Returns the fin[Usaco2007 Jan]Balanced Lineup
嘟嘟嘟 一道RMQ板子题,分别维护最大值和最小值,不解释。 1 #include<cstdio> 2 #include<iostream> 3 #include<algorithm> 4 #include<cmath> 5 #include<cstring> 6 #include<cstdlib> 7 #include<cctype> 8 #include<stack> 9 #inclP3067 [USACO12OPEN]Balanced Cow Subsets G
原题链接 折半搜索:一个我做一道相关题能T10次的算法 参考了大佬的题解,本蒟蒻没想出来怎么去重(搜索也没想到...绕在只放第x组的死循环里),但是大佬的题解也是T了第5点,开了O2才过... 思路: 首先明确重复的方法与所取砝码的质量无关,只与取的分别是谁有关.也就是说 测856. Score of Parentheses
Given a balanced parentheses string S, compute the score of the string based on the following rule: () has score 1 AB has score A + B, where A and B are balanced parentheses strings. (A) has score 2 * A, where A is a balanced parentheses string. EGold Balanced Lineup POJ - 3274
原题链接 考察:hash+前缀和 做完这道题感觉终于懂一点hash了,散列表hash是将值存储在映射的键里,会有不同值映射到相同键,因此必须要处理冲突 这道题牛二进制的前缀和会根据ash函数映射到相同键,这些前缀和有些和答案要求根本不符,所以我们必须筛掉那些不符合的键,也就是说这道题我