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LeetCode 42. Trapping Rain Water - 单调栈(Monotonic Stack)系列题4

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it can trap after raining. Example 1: Input: height = [0,1,0,2,1,0,1,3,2,1,2,1] Output: 6 Explanation: The above elevation map (black sec

[Leetcode 42]雨天积水面积Trapping Rain Water

题目 下雨天的蓄水量计算 Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it can trap after raining.   Example 1: Input: height = [0,1,0,2,1,0,1,3,2,1,2,1] Output: 6 Explanation: The abov

LeetCode 407. Trapping Rain Water II【数组/BFS/堆/最短路】困难

本文属于「征服LeetCode」系列文章之一,这一系列正式开始于2021/08/12。由于LeetCode上部分题目有锁,本系列将至少持续到刷完所有无锁题之日为止;由于LeetCode还在不断地创建新题,本系列的终止日期可能是永远。在这一系列刷题文章中,我不仅会讲解多种解题思路及其优化,还会用多种

使用trap为shell的信号设置陷阱和陷阱运行原理以及如何复原默认信号处理

陷阱信号 当你的程序运行时,按下Control-C或者Control-, 一旦该信号到达程序就立刻终止运行。但是在很多的时候,你可能并不希望在信号到达的时候,程序就立刻停止运行。而是它能希望忽略这个信号而一直运行,或者在程序退出以前,做一些清除操作。trap命令允许你控制你的程序在收到

【力扣42. 接雨水】单调栈+dp+双指针(Python3)

题目描述 https://leetcode-cn.com/problems/trapping-rain-water/ 思路题解 单调栈 https://leetcode-cn.com/problems/trapping-rain-water/solution/trapping-rain-water-by-ikaruga/ class Solution: def trap(self, height: List[int]) -> int: def cal(l,

高频刷题-42. Trapping Rain Water

https://leetcode.com/problems/trapping-rain-water/ 这个问题我们采用的算法是全局遍历,找到最高点所在的index,然后对于左侧和右侧,分别计算蓄水量。对于左侧,蓄水量为左侧最大高度 – 当前高度,然后将蓄水量相加;右侧也是一样,从右向左遍历,蓄水量为右侧最大高度 – 当前高度。最后

Leetcode 42. Trapping Rain Water (cpp)

题目 解法1:暴力 这题关键在于,每个位置能盛放多少水由这个位置左边的最大值和右边的最大值中的最小值决定的。到每个位置也只需要计算当前位置能盛放多少水即可。知道了这点,剩下的就是怎么优化罢了,原理都一样 class Solution { public: int trap(vector<int>& height) {

【leetcode字节跳动题库】42. Trapping Rain Water

用个单调栈 提交代码 class Solution { public int trap(int[] height) { Stack<Integer> hStack=new Stack<Integer>(); Stack<Integer> pStack=new Stack<Integer>(); int hLeft=0,base=0,water=0; for(int i=0;i<he

Trapping Rain Water II

Description Given n x m non-negative integers representing an elevation map 2d where the area of each cell is 1 x 1, compute how much water it is able to trap after raining.   Example Example 1: Given `5*4` matrix Input:[[12,13,0,12],[13,4,13

LeetCode第42题思悟——接雨水(trapping-rain-water)

LeetCode第42题思悟——接雨水(trapping-rain-water) 文章目录LeetCode第42题思悟——接雨水(trapping-rain-water)知识点预告题目要求示例我的思路优秀解法差异分析知识点小结 知识点预告 指针在数组中移动的技巧; 化整为零的技巧; 题目要求 给定 n 个非负整数表示每个宽度为

leetcode接雨水 trapping rain water 使用双指针

原文链接:https://leetcode-cn.com/problems/two-sum/solution/jie-yu-shui-by-leetcode/ 和方法2相比,我们不从左和从右分开计算,我们想办法一次完成遍历。 从动态编程方法的示意图中我们注意到,只要right_max[i]>left_max[i],即右部的最大值大于左部的最大

trapping-rain-water

/** * * @author gentleKay * Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. * For example, * Given[0,1,0,2,1,0,1,3,2,1,2,1], return6. * * 给定n个非负整数,

[双指针] leetcode 42 Trapping Rain Water

problem:https://leetcode.com/problems/trapping-rain-water/        此题需要维护首尾两个指针,每次移动较小高度处的指针。        同时,维护左右的最大高度,作为当前可装水的高度。每次更新较小高度处的装水量,因为当前位置高度比另一侧更小,起码可以保证水不会从另一边漏出

70.Trapping Rain Water(容水量)

Level:   Hard 题目描述: Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this

42. Trapping Rain Water

    C++: 1 class Solution { 2 public: 3 int trap(vector<int>& height) { 4 int left = 0 ; 5 int right = height.size() - 1; 6 int res = 0 ; 7 int maxLeft = 0 , maxRight = 0 ; 8 while(left <= right){

LeetCode重点题系列之【42. Trapping Rain Water】

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of ra

19.2.4 [LeetCode 42] Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rain

42. Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rai