1608

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[LeetCode] 1608. Special Array With X Elements Greater Than or Equal X

You are given an array nums of non-negative integers. nums is considered special if there exists a number x such that there are exactly x numbers in nums that are greater than or equal to x. Notice that x does not have to be an element in n

LeetCode 1608. 特殊数组的特征值

1608. 特殊数组的特征值给你一个非负整数数组 nums 。如果存在一个数 x ，使得 nums 中恰好有 x 个元素大于或者等于 x ，那么就称 nums 是一个特殊数组，而 x 是该数组的特征值。注意： x 不必是 nums 的中的元素。如果数组 nums 是一个特殊数组，请返回它的特征值 x 。否

1608. Special Array With X Elements Greater Than or Equal X

题目：You are given an array nums of non-negative integers. nums is considered special if there exists a number x such that there are exactly x numbers in nums that are greater than or equal to x. Notice that x does not have to be an element i

Leetcode 1608. 特殊数组的特征值（DAY 175）---- 二分算法学习期

文章目录原题题目代码实现（首刷自解）原题题目代码实现（首刷自解） class Solution { public: int specialArray(vector<int>& nums) { int max_x = nums.size(),ret = -1,num = 0,pos = 0; sort(nums.begin(),nums.end()); while(num <=

【leetcode】1608. Special Array With X Elements Greater Than or Equal X

题目如下： You are given an array nums of non-negative integers. nums is considered special if there exists a number x such that there are exactly x numbers in nums that are greater than or equal to x. Notice that x does not have to be an ele

1608. 特殊数组的特征值

难度 easy 给你一个非负整数数组 nums 。如果存在一个数 x ，使得 nums 中恰好有 x 个元素大于或者等于 x ，那么就称 nums 是一个特殊数组，而 x 是该数组的特征值。注意： x 不必是 nums 的中的元素。如果数组 nums 是一个特殊数组，请返回它的特征值 x 。否则，返回 -1 。可以证

LeetCode #1608. Special Array With X Elements Greater Than or Equal X

题目 1608. Special Array With X Elements Greater Than or Equal X 解题方法设置x从0开始遍历到len(nums)，每次循环内再遍历nums数组，统计有多少个数大于等于x记为count，如果统计的结果大于x就break此次循环。遍历数组的循环结束后判断x是否等于count，如果是就返回x，不是的话就返回

1608. Special Array With X Elements Greater Than or Equal X

You are given an array nums of non-negative integers. nums is considered special if there exists a number x such that there are exactly x numbers in nums that are greater than or equal to x. Notice that x does not have to be an element in n

AcWing 1608. 森林里的鸟并查集

地址 https://www.acwing.com/solution/content/15062/ 一些科学家为森林中成千上万的鸟类拍照。假设所有出现在同一张照片中的鸟都属于同一棵树。请你帮助科学家计算森林中树木的最大数量，对于任何一对鸟类，请判断它们是否在同一棵树上。输入格式第一行包含整数 N 表示照

UVA 1608 Non-boring sequences 分治

https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=4483 题目大意：给一个数字序列，若该序列的任意一个连续子序列中都有唯一出现的值，那么这个序列是non−boringnon-boringnon−boring的，否则这个序列是boringboringboring的

带权最短路计数，洛谷1608

#include<cstdio>#include<iostream>#include<cstring>#include<algorithm>using namespace std;int inf=99999999;int e[2001][2001],dis[10000000],book[10000000],ans[1000000];int main(){ int i,j,n,m,t1,t2,t3,u,v,mmin; scanf("%d%

UVA - 1608 Non-boring sequences（分治法）

题目：如果一个序列的任意连续的子序列中至少有一个只出现一次的元素，则称这个序列是不无聊的。输入一个n（n≤200000）个元素的序列A（各个元素均为109以内的非负整数），判断它是不是不无聊的。思路：分治法，平常确实用的非常的少，这次借这个题目熟悉一下。代码思路是学习的紫书上的代码的。在