C语言实现扫雷游戏（可标记雷）有三种难度等级！选中空白可开辟一片空间，高仿扫雷
作者：互联网
源文件
#define _CRT_SECURE_NO_WARNINGS 1
#include "game.h"
void menu()
{
printf("***************************\n");
printf("******** 1.play *********\n");
printf("******** 0.exit *********\n");
printf("***************************\n");
}
void menu1()
{
printf("*** 1.简单 2.中等 3.困难 ***\n");
}
void game()
{
//雷的信息存储
//1.布置好的雷的信息
char mine[ROWS][COLS] = { 0 };//11*11
//2.排查的雷的信息
char show[ROWS][COLS] = { 0 };
//初始化
InitBoard(mine, ROWS, COLS, '0');
InitBoard(show, ROWS, COLS, '*');
//打印棋盘
DisplayBoard(show,ROW,COL);
//布置雷
SetMine(mine, ROW, COL);
//DisplayBoard(mine, ROW, COL); //显示排雷的结果（答案）
//扫雷
FindMine(mine,show,ROW,COL);
}
extern int win;
int ROW = 9;
int COL = 9;
int EASY_COUNT = 10;
int surplus = 0; //剩余雷的个数
void text()
{
int input = 0;
int input1 = 0;
srand((unsigned int)time(NULL));
do{
menu();
win = 0;
printf("请选择:>");
scanf("%d", &input);
switch (input)
{
case 1:
menu1(); //显示选择模式信息
printf("请选择:>");
scanf("%d", &input1);
switch (input1)
{
case 1:
ROW = 9;
COL = 9;
EASY_COUNT = 10;
surplus = 10;
break;
case 2:
ROW = 16;
COL = 16;
EASY_COUNT = 40;
surplus = 40;
break;
case 3:
ROW = 16;
COL = 30;
EASY_COUNT = 99;
surplus = 99;
break;
}
game();
break;
case 0:
printf("退出游戏\n");
break;
default:
printf("选择错误，重新选择！\n");
}
} while (input);
}
int main()
{
text();
return 0;
}game.c
#define _CRT_SECURE_NO_WARNINGS 1
#include "game.h"
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
int i = 0, j = 0;
for (i = 0; i < rows; i++)
{
for (j = 0; j < cols; j++)
{
board[i][j] = set;
}
}
}
void DisplayBoard(char board[ROWS][COLS], int row, int col)
{
printf("剩余雷的个数:%d\n",surplus);
int i = 0, j = 0;
//打印列号
for (i = 0; i <= col; i++)
{
printf("%3d", i);
}
printf("\n");
for (i = 1; i <= row; i++)
{
printf("%3d ", i);
for (j = 1; j <= col; j++)
{
printf(" %c ", board[i][j]);
}
printf("\n");
}
}
void SetMine(char board[ROWS][COLS], int row, int col)
{
int count = EASY_COUNT;
while (count)
{
int x = rand() % (row - 1) + 1;//1-row
int y = rand() % (col - 1) + 1;//1-col
if (board[x][y] == '0')
{
board[x][y] = '1';
count--;
}
}
}
int get_mine_count(char mine[ROWS][COLS], int x, int y)
{
return mine[x - 1][y - 1] + mine[x - 1][y] + mine[x - 1][y + 1] +
mine[x][y - 1] + mine[x][y + 1] +
mine[x + 1][y - 1] + mine[x + 1][y] + mine[x + 1][y + 1]
- 8 * '0';
}
//展开的功能，递归
//1.坐标不是雷 2.该坐标周围也没有雷
//展开：他周围的坐标是否满足以上两个条件
int win = 0;
void disp(char mine[ROWS][COLS], char show[ROWS][COLS], int x1, int y1)
{
int arr[8][2] = { { x1 - 1, y1 - 1 }, { x1 - 1, y1 }, { x1 - 1, y1 + 1 }, { x1, y1 - 1 },
{ x1, y1 + 1 }, { x1 + 1, y1 - 1 }, { x1 + 1, y1 }, { x1 + 1, y1 + 1 } };
int i = 0;
//遍历四周
for (i = 0; i < 8; i++)
{
int x1 = arr[i][0], y1 = arr[i][1]; //一个棋子
//如果它不是雷且没有被遍历过，那么就显示周围雷的个数
if (x1 >= 1 && x1 <= ROW && y1 >= 1 && y1 <= COL && mine[x1][y1] == '0' && show[x1][y1] == '*')
{
int count = get_mine_count(mine, x1, y1);
show[x1][y1] = count + '0'; //显示周围雷的个数，已遍历
win++;
//且如果他的周围没有雷，那么就展开
if (mine[x1 - 1][y1 - 1] == '0' && mine[x1 - 1][y1] == '0' && mine[x1 - 1][y1 + 1] == '0' &&
mine[x1][y1 - 1] == '0' && mine[x1][y1 + 1] == '0' &&
mine[x1 + 1][y1 - 1] == '0' && mine[x1 + 1][y1] == '0' && mine[x1 + 1][y1 + 1] == '0') //周围没有雷
{
show[x1][y1] = ' '; //显示空格
disp(mine, show, x1, y1);
}
}
}
}
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
int x = 0, y = 0,input=0;
while (win < row*col-EASY_COUNT)
{
printf("请输入排查雷的坐标、排雷0 或 设置雷的标注1:>");
scanf("%d%d%d", &x, &y,&input);
if (x >= 1 && x <= row && y >= 1 && y <= col ) //坐标合法
{
if (input == 0) //排雷
{
if (mine[x][y] == '1') //踩雷
{
printf("很遗憾你被炸死了\n");
DisplayBoard(mine, row, col);
break;
}
else //非雷
{
//计算x,y坐标周围有几个雷
int count = get_mine_count(mine, x, y);
if (count == 0)
{
show[x][y] = ' ';
}
else
{
show[x][y] = count + '0';
}
win++;
if (mine[x - 1][y - 1] == '0' && mine[x - 1][y] == '0' && mine[x - 1][y + 1] == '0' &&
mine[x][y - 1] == '0' && mine[x][y + 1] == '0' &&
mine[x + 1][y - 1] == '0' && mine[x + 1][y] == '0' && mine[x + 1][y + 1] == '0')
{
disp(mine, show, x, y);
}
}
}
else if (input == 1)
{
if (show[x][y] == '*')
{
show[x][y] = '!';
surplus--;
}
else if (show[x][y] == '!')
{
show[x][y] = '*';
surplus++;
}
}
DisplayBoard(show, row, col);
}
else
{
printf("输入坐标非法，请重新输入\n");
}
}
if (win == row*col - EASY_COUNT)
{
printf("恭喜你，排雷成功\n");
DisplayBoard(mine, row, col);
}
}game.h
extern int ROW;
extern int COL;
extern int EASY_COUNT;//雷的个数
extern int surplus;//剩余雷的个数
#define ROWS 18
#define COLS 32
#include <stdio.h>
#include <stdlib.h>
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);
void DisplayBoard(char board[ROWS][COLS], int row, int col);
void SetMine(char board[ROWS][COLS], int row, int col);
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);标签：ROWS,int,void,COLS,C语言,char,扫雷,高仿,printf 来源： https://blog.51cto.com/15080913/2673448