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LeetCode 966. 元音拼写检查器(哈希)

作者:互联网

1. 题目

在给定单词列表 wordlist 的情况下,我们希望实现一个拼写检查器,将查询单词转换为正确的单词。

对于给定的查询单词 query,拼写检查器将会处理两类拼写错误:

例如:wordlist = ["yellow"], query = "YellOw": correct = "yellow"
例如:wordlist = ["Yellow"], query = "yellow": correct = "Yellow"
例如:wordlist = ["yellow"], query = "yellow": correct = "yellow"
例如:wordlist = ["YellOw"], query = "yollow": correct = "YellOw"
例如:wordlist = ["YellOw"], query = "yeellow": correct = "" (无匹配项)
例如:wordlist = ["YellOw"], query = "yllw": correct = "" (无匹配项)

此外,拼写检查器还按照以下优先级规则操作:

给出一些查询 queries,返回一个单词列表 answer,其中 answer[i] 是由查询 query = queries[i] 得到的正确单词。

示例:
输入:wordlist = ["KiTe","kite","hare","Hare"], queries = ["kite","Kite","KiTe","Hare","HARE","Hear","hear","keti","keet","keto"]
输出:["kite","KiTe","KiTe","Hare","hare","","","KiTe","","KiTe"]
 
提示:
1 <= wordlist.length <= 5000
1 <= queries.length <= 5000
1 <= wordlist[i].length <= 7
1 <= queries[i].length <= 7
wordlist 和 queries 中的所有字符串仅由英文字母组成。

来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/vowel-spellchecker
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。

2. 解题

class Solution {	//C++
public:
    vector<string> spellchecker(vector<string>& wordlist, vector<string>& queries) {
    	// 元音集合
    	unordered_set<char> vowel = {'a','e','i','o','u'};
    	// 原始单词集合
    	unordered_set<string> words(wordlist.begin(), wordlist.end());
    	//转成小写后的单词 ---- 第一个出现的原始词
    	unordered_map<string,string> upper_lower;
    	//转小写且元音标为*  ----- 第一个出现的原始词
    	unordered_map<string,string> vowel_mask;
    	string s1, s2;
    	int i = 0, idx = 0;
    	for(auto& w : wordlist)
    	{
    		words.insert(w);
    		s1 = s2 = w;
    		for(i = 0; i < w.size(); i++)
    		{
    			if(isupper(s1[i]))
    			{
    				s1[i] += 32;//转小写
    				s2[i] += 32;
    			}
    			if(vowel.count(s2[i]))
    				s2[i]='*';
    		}
    		if(!upper_lower.count(s1))
    			upper_lower[s1] = w;
    		if(!vowel_mask.count(s2))
    			vowel_mask[s2] = w;
    	}
    	vector<string> ans(queries.size(),"");
    	for(auto& q : queries)
    	{
    		if(words.count(q))
    			ans[idx] = q;
    		else
    		{
    			s1 = s2 = q;
    			for(i = 0; i < q.size(); i++)
	    		{
	    			if(isupper(s1[i]))
	    			{
	    				s1[i] += 32;//转小写
	    				s2[i] += 32;
	    			}
	    			if(vowel.count(s2[i]))
	    				s2[i]='*';
	    		}
	    		if(upper_lower.count(s1))
	    			ans[idx] = upper_lower[s1];
    			else if(vowel_mask.count(s2))
    				ans[idx] = vowel_mask[s2];
	    	}
	    	idx++;
    	}
    	return ans;
    }
};

144 ms 29.1 MB

标签:wordlist,966,vowel,s2,s1,单词,哈希,query,LeetCode
来源: https://blog.csdn.net/qq_21201267/article/details/106875371