2019哲学家用餐

sem bowl;
sem chopsticks[n];
for(int i=0;i<n;i++)
    chopsticks[i].value=1;
bowl.value=min(n-1,m)//bowl.value<=n-1,确保不死锁
while(True)
{
    p(bowl);
    p(chopsticks[i]);
    p(chopsticks[(i+1]MOD n);
    就餐；
    v(chopsticks[i]);
    v(chopsticks[(i+1]MOD n);
    v(bowl);
}

标签：哲学家,int,用餐,bowl,2019,chopsticks,sem
来源： https://www.cnblogs.com/yangmenda/p/11708061.html