prim畅通工程

原文链接：http://www.cnblogs.com/-wang-xin/archive/2012/12/07/2807474.html

#include<iostream>

using namespace std;

#define INF 0x3f3f3ff

const int MAX_V_NUM=105;

int Edges[MAX_V_NUM][MAX_V_NUM];

struct Node{

         int adjvex;//存储该边依附在U中的顶点

         int lowcost;//边的权值，访问标记

}closedge[MAX_V_NUM];

int prim(int u,int n)

{

         int i,j,k,min,sum=0;

         for(i=1;i<=n;i++)

         {

                   closedge[i].adjvex=u;

                   closedge[i].lowcost=Edges[u][i];

         }

         closedge[u].lowcost=-1;

         for(i=1;i<n;i++)

         {

                   min=INF;

                   for(j=1;j<=n;j++)

                            if(closedge[j].lowcost!=-1&&closedge[j].lowcost<min)

                            {

                                     min=closedge[j].lowcost;

                                     k=j;

                            }

                            //cout<<"("<<closedge[k].adjvex<<","<<k<<","<<min<<")"<<endl;

                            sum+=min;

                            closedge[k].lowcost=-1;

                            for(j=1;j<=n;j++)//修改其他顶点的最小边

                            {

                                     if(Edges[k][j]!=0&&Edges[k][j]<closedge[j].lowcost)

                                     {

                                               closedge[j].adjvex=k;

                                               closedge[j].lowcost=Edges[k][j];

                                     }

                            }       

         }

         cout<<sum<<endl;

         return 0;

}

int main()

{

         int n,i,j,u,v,w;

         while(true)

         {

                   cin>>n;

                   if(n==0)

                            break;

                   for(i=1;i<=n;i++)

                            for(j=1;j<=n;j++)

                            {

                                     if(i==j)

                                               Edges[i][j]=0;

                                     else

                                               Edges[i][j]=INF;

                            }

                            for(i=1;i<=(n*(n-1))/2;i++)

                            {

                                     cin>>u>>v>>w;

                                     Edges[u][v]=Edges[v][u]=w;

                            }

                            prim(1,n);

         }

         return 0;

}

 

 

 

转载于:https://www.cnblogs.com/-wang-xin/archive/2012/12/07/2807474.html

标签：prim,工程,min,int,closedge,Edges,lowcost,畅通,NUM
来源： https://blog.csdn.net/weixin_30354675/article/details/99839314