Leetcode-多数元素
作者:互联网
一道简单题直接把今日KPI拉满了,做完直接消除emo,hhh
Python的思路就很简单啊,建个字典,把各数出现的次数全部统计到字典里,最后判断一下,over~~
class Solution:
def majorityElement(self, nums: List[int]) -> int:
k = int(len(nums)/2)
d = dict()
for i in nums:
if(i in d):
d[i] = d[i]+1
else:
d[i] = 1
for i in d:
if(d[i]>k):
return i
运行结果:
看了下这题的评论。。。。仿佛不是同一道题。。。。
标签:nums,int,over,元素,这题,多数,Leetcode,各数,字典 来源: https://blog.csdn.net/weixin_44166338/article/details/123584131