【十二月】第二次课堂练习

P1605

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <cstring>
using namespace std;
int barrier[10][10];
int walkx[5] = {0,0,0,1,-1};  //x方向可以走的选择
int walky[5] = {0,-1,1,0,0};  //y方向可以走的选择
int n,m,t,sx,sy,fx,fy;  //n行，m列，t障碍数，sx,sy起点坐标，fx,fy终点坐标 
int result = 0;
int flag[10][10];

void dfs(int x, int y){
    if(x == fx && y == fy){
        result++;
        return;  //返回 
    }
    else{
        for(int i = 1; i <= 4; ++i){  //上下左右四个方向可以走 
            if(flag[x+walkx[i]][y+walky[i]] == 0
             && barrier[x+walkx[i]][y+walky[i]] == 1){  //是否已走过 && 是否有障碍 
                flag[x][y] = 1;  //原先的标记为已走过 
                dfs(x+walkx[i],y+walky[i]);
                flag[x][y] = 0;  //回溯 
            }
        }
    }
}

int main(){
    scanf("%d%d%d",&n,&m,&t);
    scanf("%d%d%d%d",&sx,&sy,&fx,&fy);
    for(int i = 1; i <= n; ++i){
        for(int j = 1; j <= m; ++j){
            barrier[i][j] = 1;  //初始化为地图都不为障碍，即都可以走 
        }
    }
    int barrierx,barriery;
    for(int i = 1; i<= t; ++i){
        scanf("%d%d",&barrierx,&barriery);
        barrier[barrierx][barriery] = 0;  //更新障碍处 
    }
    dfs(sx,sy);  //从起点开始深搜 
    printf("%d\n",result);
    return 0;
}

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标签：10,课堂练习,十二月,int,fy,fx,result,第二次,include
来源： https://www.cnblogs.com/orange-/p/15674577.html