顺序栈C++实现
作者:互联网
顺序栈C++实现
myStack.h
#pragma once
#include<iostream>
using namespace std;
#define MAXSIZE 100
#include<string>
template<typename T>
class myStack
{
public:
//栈的初始化
myStack();
myStack(const myStack& s);
//判断栈是否为空
bool isEmpty();
//求栈的长度
int size();
//获取栈顶元素
T topValue();
//打印栈中元素(逆序)
void printElem();
//清空栈
void clear();
//入栈
void push(T data);
//出栈
void pop();
//栈销毁
~myStack();
//运算符重载
myStack<T>& operator=(myStack<T>& ms);
private:
T *base;
T *top;
int stacksize;
};
//=运算符重载
template<typename T>
myStack<T>& myStack<T>::operator=(myStack<T>& ms)
{
ms.top -= ms.stacksize;
for (int i = 0; i < ms.stacksize; i++)
{
*top = *ms.top;
ms.top++;
top++;
}
this->stacksize = ms.stacksize;
return *this;
}
//栈的初始化
template<typename T>
myStack<T>::myStack()
{
base = new T[MAXSIZE];
top = base;
stacksize = 0;
}
template<typename T>
myStack<T>::myStack(const myStack& s)
{
base = new T[MAXSIZE];
top = base;
T *temp;
temp = s.top;
temp -= s.stacksize;
for (int i = 0; i < s.stacksize; i++)
{
*top = *temp;
temp++;
top++;
}
this->stacksize = s.stacksize;
}
//判断栈是否为空
template<typename T>
bool myStack<T>::isEmpty()
{
if (base == top)
return true;
else
return false;
}
//求栈的长度
template<typename T>
int myStack<T>::size()
{
return stacksize;
}
//获取栈顶元素
template<typename T>
T myStack<T>::topValue()
{
return *(top - 1);
}
//打印栈中元素(逆序)
template<typename T>
void myStack<T>::printElem()
{
if (!isEmpty())
{
for (int i = 1; i <= stacksize; i++)
{
cout << *(top - i) << " ";
}
cout << endl;
}
else
{
cout << "栈为空!" << endl;
}
}
//清空栈
template<typename T>
void myStack<T>::clear()
{
stacksize = 0;
top = base;
cout << "清楚成功\n";
}
//入栈
template<typename T>
void myStack<T>::push(T data)
{
if (top - base != MAXSIZE)
{
*top++ = data;
stacksize++;
cout << "添加成功\n";
}
else
{
cout << "栈已满,插入失败!" << endl;
}
}
//出栈
template<typename T>
void myStack<T>::pop()
{
top--;
stacksize--;
cout << "出栈成功\n";
}
//栈销毁
template<typename T>
myStack<T>::~myStack()
{
delete[] base;
}
标签:顺序,实现,top,C++,base,template,myStack,stacksize,void 来源: https://blog.csdn.net/gengjingsai/article/details/121844027