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HDOJ - 4414 (Finding crosses)
原文链接:http://www.cnblogs.com/yewei/archive/2012/10/01/2709753.html 思路 : 直接枚举 1 /* 2 PROG: Finding crosses 3 ID : 4 LANG: C++ 5 */ 6 //#pragma warnning (diaable : 4530) 7 //#pragma warnning (disable : 478R - Yet Another Crosses Problem(有难度的思维题)
这道题,题的意思就是去找需要刷的数目最小并且能使得这点所对应的行和列均为*; 通过理解,不难发现:最小不就是行对应枚举列是行和列和(我这里是 . 的个数的和)最小吗?(有了这个想法之后就好办了);所以我可以用两个一维数组存下每行对应的个数,没列对应的个数; 然后枚举矩阵里面的每Educational codeforces Round68 Div.2 Yet Another Crosses Problem
题目描述 You are given a picture consisting of n rows and mm columns. Rows are numbered from 11 to n from the top to the bottom, columns are numbered from 11 to mm from the left to the right. Each cell is painted either black or white. You think that this picB. Yet Another Crosses Problem
B. Yet Another Crosses Problem time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output You are given a picture consisting of n rows and m columns. Rows are numbered from 1 to n from the top to the bCodeforces - 1194B - Yet Another Crosses Problem - 水题
https://codeforc.es/contest/1194/problem/B 好像也没什么思维,就是一个水题,不过蛮有趣的。意思是找缺黑色最少的行列十字。用O(n)的空间预处理掉一维,然后用O(n)的时间根据另一维计算出答案。 #include<bits/stdc++.h> using namespace std; typedef long long ll; int n, m; str335. Self Crossing
You are given an array x of n positive numbers. You start at point (0,0) and moves x[0] metres to the north, then x[1] metres to the west, x[2] metres to the south, x[3] metres to the east and so on. In other words, after each move your directio