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POJ 1703 Find them, Catch them （种类并查集）

题目传送：POJ 1703 Describe: The police office in Tadu City decides to say ends to the chaos, as launch actions to root up the TWO gangs in the city, Gang Dragon and Gang Snake. However, the police first needs to identify which gang a criminal belongs to.

POJ 1703

Find them, Catch them Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 62172   Accepted: 18837 Description The police office in Tadu City decides to say ends to the chaos, as launch actions to root up the TWO gangs in the city, Gang

1293E. Xenon's Attack on the Gangs (树形DP)

题目：传送门  思路：边权是任意填的。 包含0边（边权为0）的树链的mes值至少为1。换言之，0边为这些树链增加了1点的贡献，而1边（边权为1）必须与0边在一条链才能增加贡献，2边必须与1、0边在一条链才能增加贡献。而3、1、0构成一条链的mes为2，与 0、1构成一条链的mes相同，可见 在下图3边 是对答

【cf1293E】E.Xenon's Attack on the Gangs（dp）

传送门 题意： 给出一颗树，树上随机分配\(0\)到\(n-1\)的边权，不存在权值相同的两条边。 定义\(mex(u,v)\)为：树上\(u\)到\(v\)的简单路径中所有边权的\(mex\)。 求 \[ \sum_{1\leq u\leq v\leq n}mex(u,v) \] 思路： 将问题转化为求一条边的贡献，显然一条边对跨过这条边的所有点对有贡献

CodeForces 1292C Xenon's Attack on the Gangs

Description Solution 观察一下答案式子： $$\begin{array}{rl} S = & \!\! \sum\limits_{1\le u<v \le n} \operatorname{mex}(u, v) \\= & \!\! \sum\limits_{x = 1}^{n} \left( \sum\limits_{\operatorname{mex}(u, v) = x} x \right) \cdots\cdots

[LuoguP3064][USACO12DEC]伊斯坦布尔的帮派Gangs of Istanbull(加强版)_线段树_贪心

伊斯坦布尔的帮派Gangs of Istanbull 题目链接：https://www.luogu.org/problem/P3064 数据范围：略。 题解： 这个题其实分为两问，第一问是$YES$、$NO$和最大值，第二问是最小字典序方案。 整体思路肯定是，后$2\sim m$的帮派先自行抵消，最少能剩下多少奶牛，然后再用$1$去抵消。 先说第一问：

1034 Head of a Gang (30 point(s)) - C语言 PAT 甲级

1034 Head of a Gang (30 point(s)) One way that the police finds the head of a gang is to check people’s phone calls. If there is a phone call between A and B, we say that A and B is related. The weight of a relation is defined to be the total time len

@codeforces - 804F@ Fake bullions

目录 @description@ @solution@ @part - 1@ @description@ 有 n 个 gangs，第 i 个 gangs 有 si 个人，编号为 0...si - 1。在所有的人中，有些人曾经通过特殊途径拿到了一根真正的 gold。 现在距离他们拿到 gold 已经过去 \(10^{100}\)（假装他们都不会死）。在这些年中，他们进行了

Find them, Catch them-POJ - 1703-并查集

Find them, Catch them The police office in Tadu City decides to say ends to the chaos, as launch actions to root up the TWO gangs in the city, Gang Dragon and Gang Snake. However, the police first needs to identify which gang a criminal belongs to. The

poj1703

Find them, Catch them Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 21916   Accepted: 6523 Description The police office in Tadu City decides to say ends to the chaos, as launch actions to root up the TWO gangs in the city, Gang Dragon a