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本体开发日记05-努力理解SWRL（RDF Concrete Syntax）

RDF Concrete SyntaxRDF 具体语法 SWRL 的 RDF 模式是 swrl.rdf。SWRL 的 OWL 本体是 swrl.owl。每一个都只提供了 SWRL 语法的部分描述；OWL 本体比 RDF Schema 更完整。通过扩展OWL XML 表示语法 [ OWL XML ]的XSLT 转换，可以轻松完成从 XML 具体语法到 RDF/XML 的 转换。 swr

LeetCode不定时刷题——Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-spac

Crane POJ - 2991 区间更新 + 计算几何

一、内容 ACM has bought a new crane (crane -- jeřáb) . The crane consists of n segments of various lengths, connected by flexible joints. The end of the i-th segment is joined to the beginning of the i + 1-th one, for 1 ≤ i < n. The beginning of the

A - Perfect Team CodeForces - 1221C

You may have already known that a standard ICPC team consists of exactly three members. The perfect team however has more restrictions. A student can have some specialization: coder or mathematician. She/he can have no specialization, but can't have

Separate String

题目描述 You are given a string t and a set S of N different strings. You need to separate t such that each part is included in S. For example, the following 4 separation methods satisfy the condition when t=abab and S={a,ab,b}. a,b,a,b a,b,ab ab,a,b ab,a

【LeetCode每天一题】Length of Last Word(字符串中最后一个单词的长度)

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space

19.2.9 [LeetCode 58] Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-spac