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POJ2888 Magic Bracelet
POJ2888 Magic Bracelet Problem 用 \(m\) 种颜色串 \(n\) 个珠子，其中有 \(k\) 个限制，每个限制需要满足 \(a\) 颜色的珠子不能与 \(b\) 颜色的珠子相串。 \(1\le n\le 10^9,1\le m \le 10\)。 Solution 考虑 Burnside 引理，\(ans=\frac{1}{n}\sum\limits_{g\in G}|X^g|\)。 本题 \(P2871 [USACO07DEC]Charm Bracelet S 题解
P2871 [USACO07DEC]Charm Bracelet S #include<iostream> using namespace std; long long dp[12881]; int D[3500],W[3500]; int main() { int N,M; cin>>N>>M; for (int i=1;i<=N;i++) { cin>>W[i]>>D[i]; } for (int i=1;i<=codeforces.contest1305problemA/B
A. Kuroni and the Gifts Kuroni has nn daughters. As gifts for them, he bought nn necklaces and nn bracelets: the ii-th necklace has a brightness aiai, where all the aiai are pairwise distinct (i.e. all aiai are different), the ii-th braceletPOJ 3624 Charm Bracelet
代码： 错误代码：超空间：由于定义了一个二维的dp数组，然后超了，所以我们要把二维转换为一维 #include<iostream> #include<stdio.h> #include<string.h> using namespace std; const int maxn = 3500; int dp[3405][12900]; struct node{ int w; int charm; }a[maxn]; intdp--01背包--Charm Bracelet
Charm Bracelet Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight WiPOJ - 3624 Charm Bracelet (01背包基础)
题意： 即是给你一个容量M的包，有N件物品，每件物品有分别对应的 价值value 以及 重量weight .然后在不超过该背包容量的情况下能得到的最大价值为多少？ 思路： 由于这是最基础的问题，所以就记录当对 01背包状态转移方程式的 理解。 对于动态规划来说，首先要知道我们要确定哪些状态量。然后Cyclic Nacklace 杭电3746
CC always becomes very depressed at the end of this month, he has checked his credit card yesterday, without any surprise, there are only 99.9 yuan left. he is too distressed and thinking about how to tide over the last days. Being inspired by the entrepr洛谷 P2871 [USACO07DEC]手链Charm Bracelet && 01背包模板
题目传送门 解题思路: 一维解01背包,突然发现博客里没有01背包的板子,补上 AC代码: 1 #include<cstdio> 2 #include<iostream> 3 4 using namespace std; 5 6 int n,m,c,w,f[15000]; 7 8 int main() 9 {10 scanf("%d%d",&n,&m);11 for(int i = 1;i <= n; i++) {Charm Bracelet一维数组背包
# include <iostream> using namespace std; int a[12881] = {0}; //前i个构成w的最大价值 = max{前i-1个构成w-wi的最大价值+vi ， 前i-1个构成w} int w[3410] = {0}; int v[3410] = {0}; int main () { int n, m; cin >> n >> m; for (int i = 0; i < n; i++) {P2871 [USACO07DEC]手链Charm Bracelet
题目传送门：P2871 [USACO07DEC]手链Charm Bracelet 题目描述 Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in tpoj2888 Magic Bracelet
题目描述： $T$组询问，每次给出$n$，$m$与$k$组关系，要求用$m$种颜色染长为$n$的手链，且$k$对颜色不能相邻。 题解 这是个坑，我认为它是对的但是$poj$不认为它是对的。 $T$的很惨。 代码： #include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int MOD = 99