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Too Many Impostors (hard version)

This is an interactive problem. The only difference between the easy and hard version is the limit on number of questions. There are nn players labelled from 11 to nn. It is guaranteed that nn is a multiple of 33. Among them, there are kk imposto

PTAt140竞赛排名：（结构体）

pta t140 竞赛排名：（结构体）思路：构造一个name&&score的struct 难点：自定义的find和加分的方法和输出方式 int find(player a[],string s,int pos){ int k; for(k=0;k<pos;k++){ if(a[k].name==s)break; } if(k==pos)return -1;

论文修改建议 (PanCF 20211025 长句子改成几个短句子)

Behavior imitation of individual board game players 可以把 behavior imitation 列为 keywordby dividing the imitation process into two stages → \to → 技术比阶段

（3）SLP Consumption and How to get more players

In Last article, I wrote about different play modes of some successful games which Axie Infinity can develop in the future. Today, let’s talk about two big problems for Axie Infinity and the solution. Q1. The cost of purchase Axie is high,

(2)Suggestions about Axie Infinity playmode development

In my last article, I wrote about a scam I meet in Axie Infinity community Discord whick cause heavy loss and I talked about Axie Infinity NFT security suggestions, today I will talk about different gameplay mode. As one of the hottest game

Codeforces

1.题目引入： A chess tournament will be held soon, where nn chess players will take part. Every participant will play one game against every other participant. Each game ends in either a win for one player and a loss for another player, or a draw for both

C 购买商品的游戏

1 #include <stdio.h> 2 #include <stdlib.h> 3 #include <string.h> 4 /* 5 *模拟实现道具店购物功能（商店暂时只支持一种类型的商品） 6 *商品具备名称，价格，库存等属性 7 *模拟玩家购买游戏道具 8 *1.玩家选择要购买的道具 9 *2.玩家同意交易后扣除相应的游

LeetCode 【困难】数据库-第1194：锦标赛优胜者

题目数据结果解答 1.因为分了两场，所以把两场连接为一场 select first_player player_id,first_score score from matches # union all select second_player player_id,second_score score from matches 2. 连接players表，按组别和玩家分组计算得分 select group_id,playe

从零开始学Redis（1）

Redis是什么 Redis（Remote Dictionary Service）互联网技术领域使用最广泛的键值对存储中间件 Redis（基于docker）的安装 docker pull redis docker run --name redisdemo -d -p6379:6379 redis docker exec -it redisdemo redis-cli Redis的五种基础数据结构 Redis有五种基础数据结构

Python入门基础教程-基础数据类型

Python简介 Python是一种面向对象的脚本语言，自20世纪90年代初诞生至今，已经逐渐被广泛应用于处理系统管理任务、爬虫、web编程、自动化测试、运维等方面。他是有CWI(阿姆斯特丹国家数学和计算机科学研究所)的研究员Guido van Russum开发的一种高级脚本编程语言。 1989年圣诞节期间，

webrtc each player could choose to be the server, and have the other players connect to them.

https://www.snopekgames.com/game/retro-tank-party/devlog/2019/switched-webrtc-networking-and-changed-name-retro-tank-party Switched to WebRTC for networking (and changed name to "Retro Tank Party") Submitted by David Snopek on Wednesday, 2019-10

1 magicians = ['alice', 'david', 'carolina'] 2 for magician in magicians: 3 print(f"{magician.title()}, that was a great trick!") 4 print(f"I can't wait to see your next trick, {magician.title()}

CF788E New task

Description On the 228-th international Uzhlyandian Wars strategic game tournament teams from each country are called. The teams should consist of $5$ participants. The team of Uzhlyandia will consist of soldiers, because there are no gamers. Masha is a n

NBA球员信息获取

昨天介绍了一个不用写代码的web项目，今天说一下数据的获取。球员信息网站：https://nba.hupu.com/players/ 首先进行页面的分析：此图片的url：https://nba.hupu.com/players/ 点击左边的球队url会根据球队的不同进行相应的变化：因此，我们只需要获取到所有的球队名称就能获取

c的函数指针与内存

动态分配内存要分配10个int，一个int占几位，10个int一共多少位就拿出多少内存 #define PLAYER_COUNT 10 int *players = malloc(sizeof(int)*PLAYER_COUNT); //print 使用 for(int i=0;i<PLAYER_COUNT;i++){ players[i] = i; } PRINT_INT_ARRAY(players); free(players); 在

第10天c#实现飞行棋

代码 using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; using System.Threading; namespace week2 { class Program { /// <summary> /// 坐标轴 /// </summary

约瑟夫问题

def move(list1,step): #移动step前的元素到列表的末尾 num = step-1 while num > 0: tmp = list1.pop(0) list1.append(tmp) num = num - 1 return list1 #根据step做了元素的移动 def play(players,step,alive): #

数字游戏函数自定义版

def yuesefu(x,y): print(x) print(y) list1=[1 for i in range(1,x+1)] while len(list1) > y: list2=list1[0:3] list1.append(list2[0]) list1.append(list2[1]) list1.append(list2[2]) del list1[0:4]

怎么样对数据库索引维护那？

怎么样对数据库索引维护那？答：如果表经常更新、删除操作，那么就要主要要定期对索引进行维护检查。 Analyze Table MySQL 的Optimizer（优化元件）在优化SQL语句时，首先需要收集一些相关信息，其中就包括表的cardinality（可以翻译为“散列程度”），它表示某个索引对应的列包含多少个不同的值——

python的列表操作教学

#遍历整个列表 magicians=['alice','david','carolina'] for magician in magicians: print(magician)# 不要忘记冒号，记住要缩减 #在for循环中执行更多的操作 magicians=['alice','david','carolina'] for magician in magicians:

04 操作列表

使用range()创建数字列表 numbers = list(range(1,6)) print(numbers) 结果： [1, 2, 3, 4, 5] Process finished with exit code 0 #指定步长 even_numbers = list(range(2,11,2)) print(even_numbers) 结果： [2, 4, 6, 8, 10] Process finished with exit code 0 #简单的

Deja vu of … Go Players

An ordinary sequence rather than magic codes? Rikka's opinion is much more important than the "truth" itself. She soon felt sleepy and fell asleep to take a trip to dreamlands in passing. Rikka found two elders playing Go game when her sani

SQL查询性能调优--如何使查询更快

翻译自https://mode.com/sql-tutorial/sql-performance-tuning 从这儿开始吗？这篇是使用SQL进行数据分析教程的一部分，查看教程开始。子查询那一课让我们意识到可以通过运行更快到语句得到同样到结果集。在这节课中，你会学习识别查询优化点，以及如何优化。查询时间背后的理论

CodeForces 96A Football （C）

题目 Petya loves football very much. One day, as he was watching a football match, he was writing the players’ current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero correspond

Josephina and RPG ZOJ - 3735

Josephina and RPG ZOJ - 3735 A role-playing game (RPG and sometimes roleplaying game) is a game in which players assume the roles of characters in a fictional setting. Players take responsibility for acting out these roles within a narrative, either thro