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OverTheWire Level 6 -> Level 7解题过程
级别：Bandit Level 6 → Level 7 目标：Level Goal The password for the next level is stored somewhere on the server and has all of the following properties: owned by user bandit7 owned by group bandit6 33 bytes in size 下一级的密码保存在目标服务器的某个地方，并OverTheWire Level 3-> Level 4解题过程
级别：Bandit Level 3 → Level 4 目标：Level Goal The password for the next level is stored in a hidden file in the inhere directory. 下一级密码保存在inhere目录中的隐藏文件 允许命令：Commands you may need to solve this level ls, cd, cat, file, du, find 解题过OverTheWire Level 4 -> Level 5解题过程
级别：Bandit Level 4 → Level 5 目标：Level Goal The password for the next level is stored in the only human-readable file in the inhere directory. Tip: if your terminal is messed up, try the “reset” command. 下一级命令保存在inhere目录中只有人类可读的文件OverTheWire Level 5 -> Level 6解题过程
级别：Bandit Level 5 → Level 6 目标：Level Goal The password for the next level is stored in a file somewhere under the inhere directory and has all of the following properties: human-readable 1033 bytes in size not executable 下一级密码保存在inhere目录的某OverTheWire的natas游戏(0-5)
natas solution(0-5) 这是一个关于web安全的闯关游戏，通过闯关学习相关知识 Natas teaches the basics of serverside web-security. Each level of natas consists of its own website located at http://natasX.natas.labs.overthewire.org, where X is the level number. TOverthewire-natas28
Overthewire level 27 to level 28 这一关和之前不一样，并没有给我们源码信息，稍微加大了一点难度。 题目给我们的信息很简单，一个搜索框，搜索后会返回一些笑话。 第一步 猜测 输入字符串a，观察网络请求，发现网络请求经历了两步，第一步是post传输原本的请求，第二步是重定向到另外一个get的Overthewire-natas27
Overthewire level 27 to level 28 function checkCredentials($link,$usr,$pass){ $user=mysql_real_escape_string($usr); $password=mysql_real_escape_string($pass); $query = "SELECT username from users where username='$user' and pasOverthewire-natas26
Overthewire level 26 to level 27 点进页面发现它让我们画两条线，直接看源码 <?php // sry, this is ugly as hell. // cheers kaliman ;) // - morla class Logger{ private $logFile; private $initMsg; private $exitMsg; fOverthewire-natas24
Overthewire level 24 to level 25 这一关与上一关很像，同样是提交一个密码登录，让我们看看源代码 <?php if(array_key_exists("passwd",$_REQUEST)){ if(!strcmp($_REQUEST["passwd"],"<censored>")){ echo "<br>The credentiOverthewire-natas18
Overthewire level 18 to level 19 这题的界面上让我们输入用户名和密码，随便输入一些字符后给了个普通用户的回显 You are logged in as a regular user. Login as an admin to retrieve credentials for natas19. 显然，这是让我们想办法成为admin用户了。先看看网页的源码。 funcOverthewire-natas16
Overthewire level 16 to level 17 点进页面，让我们输入一个单词，查看源码得知这是从一个文件中grep查看匹配的内容，代码如下 if(array_key_exists("needle", $_REQUEST)) { $key = $_REQUEST["needle"]; } if($key != "") { if(preg_match('/[;|&`\'"]/Overthewire-natas14
Overthewire level 14 to level 15 这一关需要我们输入用户名和密码来获取15关的密码，网页源代码如下 if(array_key_exists("username", $_REQUEST)) { $link = mysql_connect('localhost', 'natas14', '<censored>'); mysql_select_db('natas1