首页 > TAG信息列表 > Operation

我的设计模式之旅 ⑤ 装饰模式

一个菜鸟的设计模式之旅,文章可能会有不对的地方,恳请大佬指出错误。 编程旅途是漫长遥远的,在不同时刻有不同的感悟,本文会一直更新下去。 程序介绍 本程序实现装饰模式。小明和小王去吃沙县小吃,各自喜欢不同的搭配,需要考虑每个人饮食喜好不同,随时可能的变化。 小明想吃不带汤的面

Many Operations

Problem Statement We have a variable \(X\) and \(N\) kinds of operations that change the value of \(X\). Operation \(i\) is represented as a pair of integers \((T_i,A_i)\), and is the following operation: if \(T_i=1\), it replaces the value o

ABAP-QP01检验计划批导

1 DATA:gt_task TYPE TABLE OF bapi1191_tsk_c, 2 gs_task TYPE bapi1191_tsk_c, 3 gt_materialtaskallocation TYPE TABLE OF bapi1191_mtk_c, 4 gs_materialtaskallocation TYPE bapi1191_mtk_c, 5 gt_r

已解决:Error: EPERM: operation not permitted, mkdir **\node_modules\.***-**'

 Error: EPERM: operation not permitted, mkdir 'E:\nodejs\node_modules\.npm-x5uKn2gY' 在重装了win10系统后npm出现了此问题   npm ERR! errno -4048npm ERR! Error: EPERM: operation not permitted, mkdir 'E:\nodejs\node_modules\.npm-x5uKn2gY'npm ERR!

element-ui 在 el-table 标题中添加小图标

效果如下: html代码: <div class="table-box cus-table-box"> <el-table :data="ruleForm.tableData" border style="width: 100%"> <el-table-column prop="operation" label="操作" :render-header

paper read - 2022 - a real time visual boolean operation on triangular mesh models

paper read - 2022 - a real time visual boolean operation on triangular mesh models Chen, S., Chen, M., & Lu, S. (2022). A real time visual boolean operation on triangular mesh models. Computer-Aided Design and Applications, 19(3), 470–480. https://doi

js 获取带点的json 属性

var rowData = jQuery('#grid-table').jqGrid('getRowData',id); if('unsolve'==rowData['securityProblemReply.problemStatus']){ operation += '<button class="btn btn-xs btn-primary" title="编辑&qu

线段树之区间更新The Child and Sequence

Description At the children's day, the child came to Picks's house, and messed his house up. Picks was angry at him. A lot of important things were lost, in particular the favorite sequence of Picks. Fortunately, Picks remembers how to repair t

如何解决报错one of the variables needed for gradient computation has been modified by an inplace operation

  参考资料:   https://discuss.pytorch.org/t/what-is-in-place-operation/16244   https://blog.csdn.net/qq_35056292/article/details/116695219   参考资料二已经说明了问题,对我的情况是使用了+=运算符从而导致了报错。   比如:cost是ReLU函数的运算结果,按照正常的发

线段树区间更新之 Circular RMQ

Description You are given circular array a0, a1, ..., an - 1. There are two types of operations with it: inc(lf, rg, v) — this operation increases each element on the segment [lf, rg] (inclusively) by v; rmq(lf, rg) — this operation return

ef core报错“A second operation was started on this context instance before a previous operation comple

环境: asp .net core 6 ef core   代码报错:     #region 删除教师 [HttpPost] public async Task<IActionResult> Delete(int id) { var teacher = _teacherRepository.FirstOrDefaultAsync(a => a.Id == id); if (teac

[Javascript] String in Javascript

String in Javascript is immutable. Means that once they were created, they cannot be modified. This also means that simple operations like appending a character to a string are more expensive than they might appear.   The canonical example of an operation

git项目,执行命令this operation must be run in a work tree

如果你的项目结构更改过,比如项目换目录了,或者 项目名称更改了。可能会导致下面所说的问题。那么我们问题一致。你应该继续往下看。 输入git部分常用命令会出现this operation must be run in a work tree,但是当前项目本身就是git项目,项目根目录下也有.git目录。 git statusfatal:

ARC143 题解

太弱小了,仅 A 的一题还是在后辈 ly 的指导下才成功的。\(\sout{我被单调队列了}\) \(\sout{tnnd,刚才忘记保存了重新写一遍。}\) T1 Three Integers 题意 有三个数 \(A,B,C\) , 有两种操作 Operation 1:选择两个数并 \(-1\) Operation 2:选择三个数并 \(-1\) 使得这三个数全变成

AtCoder-abc255_d ±1 Operation 2

±1 Operation 2 离线 + 尺取 或者 直接二分 二分更简单 二分一下当前询问的数 \(X\) 的位置 \(index\),左边(小于等于当前数)的每一个数字的贡献都为 \(X - A_i\),右边(大于当前数)的每一个数字的贡献都为 \(A_i - X\),因此考虑求和的时候用前缀和优化一下就好 #include <iostream> #inc

【ATCOER、D - ±1 Operation 2】前缀和+排序二分

import java.io.BufferedReader; import java.io.InputStreamReader; import java.util.Arrays; public class Main { public static void main(String[] args) throws Exception { int N,Q; BufferedReader br = new BufferedReader(new InputStreamRea

栈(Stack) 和 队列(Queue)总结

In a LIFO data structure, the newest element added to the queue will be processed first. Different from the queue, the stack is a LIFO data structure. Typically, the insert operation is called push in a stack. Similar to the queue, a new element is always

Lecture 03 Intro to Relational Model

Attribute Attribute values are (normally) required to be atomic; that is, indivisible The special value null is a member of every domain. Indicated that the value is “unknown” The null value causes complications in the definition of many

创龙OMAPL138开发板测试Device is held in reset. Take the device out of reset, and retry the operation.

创龙OMAPL138开发板测试,连接DSP核连不上的问题解决办法。   Error connecting to the target: (Error -1180 @ 0x0) Device is held in reset. Take the device out of reset, and retry the operation. (Emulation package 8.2.0.00004)     解决方法: 把启动的拨码开关,0111

C# Winform 进度条

BackgroundWorker可在后台执行任务,不影响主线程任务 Winform配置 向Winform内拖拽ProgressBar控件progressBar1 向Winform内拖拽BackgroundWorker组件backgroundWorker1 过程处理 向backgroundWorker1添加三个事件      private void backgroundWorker1_DoWork(object sende

【深入理解 quickjs 系列】01. 前置概念整理

     虚拟机类型 栈式虚拟机 虚拟机会在其内部维护一个全局指令指针来指向下一条将要执行的指令所在位置。 堆栈机使用栈结构来作为暂存数据的容器,这使得我们无法对栈容器中的数据进行任意读取,我们需要遵循LIFO的数据操作原则来对数据进行处理。这导致无法从源代码直接生成最

NVME(学习笔记七)—Atomicity Operation

5.21.1.10 Write Atomicity Normal 这个特性控制AWUN和NAWUN参数的操作。设置的属性值在set Feature命令的Dword 11中表明。 如果提交Get Feature命令查询这个特性,属性值填写到completion应答CQE的Dword 0中返回。   【补充知识】 在Feature中设置原子操作的位置在Feature Identi

BrainFlow中的down_sampling()方法

该方法有3个参数: data:需要降采样的数据 period:以period个数据点为单位进行降采样,比如以取中间值的方式对period为3进行降采样话:[5,8,6,9,7,3]得到[8,7] operation:降采样采用的方式 mean:平均值 median:中间值 each:就是这个period末尾的那个值。比如以EACH方式,period为2对[5,8,6,9,7,3]

设计模式之装饰者模式

定义 装饰模式是在不必改变原类和使用继承的情况下,动态地扩展一个对象的功能。它是通过创建一个包装对象,也就是装饰来包裹真实的对象。 使用场景 需要在运行时动态的给一个对象增加额外的职责时候 需要给一个现有的类增加职责,但是又不想通过继承的方式来实现的时候(应该优先使用

wondershaper限制linux设备的上下行带宽

wondershaper 可以用来限制linux设备的上下行带宽 代码仓库https://github.com/magnific0/wondershaper.git 直接按照readme的说明进行使用即可,使用方法比较简单, Some examples: wondershaper -a eth0 -d 1024 -u 512 wondershaper -a eth1 -d 94000 -u 94000 # could