Lexicographically

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CF196A Lexicographically Maxim

思路只需要不断取字典序最大的字符就可以了。如何找字典序最大的字符：倒着查找，只要字符比后面所有的字符的字典序大或相等就做个记号，最后正着输出。代码 #include<iostream> #include<cstdio> #include<algorithm> #include<cmath> #include<cstring> #include<string> using na

全站最硬核百万字强肝RocketMq源码火热更新中~（四十四）

都是基础的pojo类的方法 get set方法 hashcode equals方法 toString方法 @Override public int compareTo(MessageQueue o) { { int result = this.topic.compareTo(o.topic); if (result != 0) { return result; } } {

E-Lexicographically Maximum Subsequence

题意找一个串的最大字典序字串题解正序考虑会遇到无法确定这个数该不该选的情况，遇到的矛盾是无法确定后面有没有比它大的字母，所以我们只需要解决这个问题即可，做题时的基本思路就是正序不想试一试倒序能不能优化，我们可以记录住以i为结尾的最大字符然后第i-1个数与之比较，就

CF959D 构造

1 CF959D 构造题目链接：https://codeforces.com/problemset/problem/959/d 2 题目描述时间限制 \(3s\) | 空间限制 \(256M\) Mahmoud has an array a consisting of \(n\) integers. He asked Ehab to find another array \(b\) of the same length such that: \(b\) is l

B. Azamon Web Services

链接：https://codeforces.com/contest/1281/problem/B Your friend Jeff Zebos has been trying to run his new online company, but it's not going very well. He's not getting a lot of sales on his website which he decided to call Azamon. His big problem,

String类比较日期

int java.lang.String.compareTo(String anotherString) Compares two strings lexicographically（字典序; 按字典顺序;）. The comparison is based on the Unicode value of each character in the strings. The character sequence represented by this String object is compared

hdu3374最大最小表示法加kmp

Give you a string with length N, you can generate N strings by left shifts. For example let consider the string “SKYLONG”, we can generate seven strings: String Rank SKYLONG 1 KYLONGS 2 YLONGSK 3 LONGSKY 4 ONGSKYL 5 NGSKYLO 6 GSKYLON 7