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[6] Nightmare
Nightmare Time Limit : 2000/1000ms (Java/Other) Memory Limit : 65536/32768K (Java/Other) Problem Description Ignatius had a nightmare last night. He found himself in a labyrinth with a time bomb on him. The labyrinth has an exit, Ignatius should get ouHow many tables HDU 1213
Today is Ignatius’ birthday. He invites a lot of friends. Now it’s dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friends do not want to stay with strangerHow Many Tables——HDU 1213
How Many Tables 题目InputOutput 思路代码结果 题目 Today is Ignatius’ birthday. He invites a lot of friends. Now it’s dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other,hdoj 1029 Ignatius and the Princess IV
找一个数组中出现次数多于 (N+1)/2的那个数 排个序，然后找出现次数最多的那个数 #include <bits/stdc++.h> using namespace std; typedef long long ll; int a[1000005]; int main() { int n,x,y,m,mx; while(cin>>n){ for(int i=0;i<n;i++) cin>>a[i];HDU1213How Many Tables（基础并查集）
HDU1213How Many Tables Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, andC - How Many Tables 杭电oj_____1213
How Many Tables Today is Ignatius’ birthday. He invites a lot of friends. Now it’s dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friends do not want to sHDU 1028 Ignatius and the Princess III(生成函数)
题目链接 题目大意 整数n可以划分成一些正整数之和，问有多少种不同的划分方法。 解题思路 用生成函数的幂做整数n，结果的系数做划分方案。 代码 const int maxn = 2e2+10; const int maxm = 2e2+10; int n, c1[maxn], c2[maxn]; int main() { for (int i = 0; i<maxn; +HDU 胜利大逃亡 （bfs）
题面 gnatius被魔王抓走了,有一天魔王出差去了,这可是Ignatius逃亡的好机会. 魔王住在一个城堡里,城堡是一个ABC的立方体,可以被表示成A个B*C的矩阵,刚开始Ignatius被关在(0,0,0)的位置,离开城堡的门在(A-1,B-1,C-1)的位置,现在知道魔王将在T分钟后回到城堡,Ignatius每分钟能从一寒假私训 —— 并查集 E - How Many Tables
E - How Many Tables 题目要求 Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friendsHDU - 1213 How Many Tables
问题 Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friends do not want to stay witHDU - 1253 胜利大逃亡 （搜索）
Ignatius被魔王抓走了,有一天魔王出差去了,这可是Ignatius逃亡的好机会. 魔王住在一个城堡里,城堡是一个A*B*C的立方体,可以被表示成A个B*C的矩阵,刚开始Ignatius被关在(0,0,0)的位置,离开城堡的门在(A-1,B-1,C-1)的位置,现在知道魔王将在T分钟后回到城堡,Ignatius每分钟能从一个【HDU 1027】Ignatius and the Princess II
Now our hero finds the door to the BEelzebub feng5166. He opens the door and finds feng5166 is about to kill our pretty Princess. But now the BEelzebub has to beat our hero first. feng5166 says, "I have three question for you, if you can work them ou[kuangbin带你飞]专题十二 基础DP1 B - Ignatius and the Princess IV
B - Ignatius and the Princess IV 题目链接：https://vjudge.net/contest/68966#problem/B 题目： "OK, you are not too bad, em... But you can never pass the next test." feng5166 says. "I will tell you an odd number N, and then N integers. There will b胜利大逃亡 HDU - 1253（广搜）
胜利大逃亡 Ignatius被魔王抓走了,有一天魔王出差去了,这可是Ignatius逃亡的好机会. 魔王住在一个城堡里,城堡是一个ABC的立方体,可以被表示成A个B*C的矩阵,刚开始Ignatius被关在(0,0,0)的位置,离开城堡的门在(A-1,B-1,C-1)的位置,现在知道魔王将在T分钟后回到城堡,Ignatius和硕拟在印尼投资最多10亿美元 为苹果生产芯片
【TechWeb】5月28日消息，据国外媒体报道，印尼工业部副部长Warsito Ignatius周二表示，台湾电子企业和硕（Pegatron）已签订意向书，拟对一家印尼工厂投资10万亿-15万亿卢比(6.95亿-10亿美元)，为苹果的智能手机生产芯片。 苹果 Ignatius对外媒表示，和硕计划与印尼电子产品公司PT Sat Nusap【HDU - 1028】Ignatius and the Princess III（生成函数）
"Well, it seems the first problem is too easy. I will let you know how foolish you are later." feng5166 says. "The second problem is, given an positive integer N, we define an equation like this: N=a[1]+a[2]+a[3]+...+a[m]; a[i]>0,How Many Tables (简单并查集)
How Many Tables #include<stdio.h> #include<algorithm> using namespace std; int fa[1010], r[1010]; void init(int x) { for(int i=1; i<=x; i++) { fa[i]=i; r[i]=0; } } int find(int x) { if(x==fa[x]) return fa[x]; else return find(fa[x并查集
一、思想 通俗的说就是将所有关系的都连接起来，比方说A和B是朋友，B和C是朋友，那么A和C也是朋友，就算是中间隔着100个朋友这样的也算是朋友。 具体实现： 通过两个函数实现。 一是查找父节点函数，此函数可以使用递归调用来压缩路径。 二是合并函数，将两个没有连接的点连接起来。 二、例题 HDNightmare
Problem Description Ignatius had a nightmare last night. He found himself in a labyrinth with a time bomb on him. The labyrinth has an exit, Ignatius should get out of the labyrinth before the bomb explodes. The initial exploding time of the bomb is set t【HDU - 1429】胜利大逃亡(续) （高级搜索）【状态压缩+BFS】
Ignatius再次被魔王抓走了(搞不懂他咋这么讨魔王喜欢)…… 这次魔王汲取了上次的教训，把Ignatius关在一个n*m的地牢里，并在地牢的某些地方安装了带锁的门，钥匙藏在地牢另外的某些地方。刚开始Ignatius被关在(sx,sy)的位置，离开地牢的门在(ex,ey)的位置。Ignatius每分钟只能从一个坐标hdu 1028 Ignatius and the Princess III
Problem Description "Well, it seems the first problem is too easy. I will let you know how foolish you are later." feng5166 says."The second problem is, given an positive integer N, we define an equation like this: N=a[1]+a[2]+a[3]+...+a[mHow Many Tables-并查集
原题链接:https://vjudge.net/problem/19354/origin Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, a