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2022-2023学年英语周报高一课标外研第21期答案汇总
进入查看:2022-2023学年英语周报高一课标外研第21期答案汇总 Clowns have been around for a long time. They not only make us laugh at the circus (马戏团) but they used to make the king and his followers laugh in court. The earliest of these fun-makers are calCF802O April Fools' Problem (hard)
更好的阅读体验 题意 有 \(n\) 道题,第 \(i\) 天可以花费 \(a_i\) 准备一道题,花费 \(b_i\) 打印一道题,每天最多准备一道题,打印一道题,准备的题可以留到以后打印,求打印 \(k\) 道题的最小花费. \(1\le k\le n\le 5\times10^5\) 题解 显然可以费用流解决,建图如下. 考虑优化费用流 引April
April is commonly associated with the season of autumn in parts of the Southern Hemisphere, and spring in parts of the Northern Hemisphere, where it is the seasonal equivalent to October in the Southern Hemisphere and vice versa. The traditional etymologyApril Fools Day Contest 2021
B. DMCA 思路: 给的样例不由得让人想到开根号上去,这题意思是每次把每一位加起来得到一个和,得到和之后再把这个和的每一位加起来,直到这个和只有个位数。 这东西叫数根。有关于他的性质和公式: 公式:(n - 1) % 9 + 1 性质:一个数加上9之后他的数根不变 不用公式做法: #include <iostreamCF191C Fools and Roads
Problem 有一颗 nn个节点的树,k 次旅行,问每一条边被走过的次数。 Solution 优化到最后才发现是个树上差分。。。树上差分:对于一条树链,u和v+1,lca的父亲(本题里面是lca)-2。本题相当于离线,如果修改和访问交替就需要树链剖分了。 Code #include<iostream> #include<cstdio> #includ【CF802O】April Fools' Problem (hard)
题目 题目链接:https://codeforces.com/contest/802/problem/O \(n\) 道题, 第 \(i\) 天可以花费 \(a_i\) 准备一道题, 花费 \(b_i\) 打印一道题, 每天最多准备一道, 最多打印一道, 准备的题可以留到以后打印, 求最少花费使得准备并打印 \(k\) 道题。 \(k,n\leq 500000,1\leq a_i,b英语知识点整理day14-谚语学习(F字母开头)
文章目录谚语学习F字母开头 谚语学习 F字母开头 1.Fact speak louder than words. 事实胜于雄辩 2.Failure is the mother of success. 失败是成功之母 3.False friends are worse than bitter enemies. 明枪易躲,暗箭难防 4.Far from eye, far from heart. 眼不见,心不烦 5.FCF191C Fools and Roads
\(\Large\textbf{Description:} \large{有一颗 n 个节点的树,k 次旅行,问每一条边被走过的次数。}\) \(\Large\textbf{Solution:} \large{树上差分板子??}\) \(\Large\textbf{Code:}\) #include <cstdio> #include <algorithm> #define LL long long #define gc() getchar() #def