Disjoint

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并查集详解图解引入到实现｜ Disjoint Sets details, intro to implementation with figures.

Introduction of Disjoint Sets It's easy to tell whether someone you know is your relative. He or she may be your uncle, grandparent or nephew. Because your blood relationship is within two or three generations. Consider such a scenario, you meet some

CF1025F Disjoint Triangles 题解

Link. Codeforces Luogu Description. 给 \(n\) 个点，求有多少对三角形不相交。 Solution. 太妙了，没想到，想到三角形对数是 \(O(n^6)\) 的，发现怎么枚举都不行。考虑两个不相交的三角形，我们可以确定它们有恰好两条公切线，使得两个三角形在切线异侧。所以我们可以直接枚举公切线，然后

并查集（Disjoint Set）

解决的问题查找图是否成环理解过程思想右边图代表着圈里面的点是连通的成环的标志是：圈内某两元素之间还有一条边转化为代码（合并两个圈）利用数组建树，数组元素值代表该位置的父亲结点，-1代表为独立结点因此：合并两圈=把a2图的头结点的父亲结点改为a1图的头结点当发现某条

915. Partition Array into Disjoint Intervals

Given an array nums, partition it into two (contiguous) subarrays left and right so that: Every element in left is less than or equal to every element in right. left and right are non-empty. left has the smallest possible size. Return the leng

Java Collections-Collections.disjoint方法检查两个指定的集合是否不相交

Java Collections类的disjoint（）方法用于检查两个指定的集合是否不相交。如果两个指定的集合没有相同的元素，则返回true。 Method: public static boolean disjoint(Collection<?> c1, Collection<?> c2) Returns true if the two specified coll

C语言实现并查集(Disjoint set或者Union-find set)(附完整源码)

实现实现并查集实现并查集(Disjoint set或者Union-find set)的完整源码（定义，实现，main函数测试）实现并查集(Disjoint set或者Union-find set)的完整源码（定义，实现，main函数测试） #include <stdio.h> #include <stdlib.h> #define MAX_SIZE 1000 /**< maximum number of ele

352. Data Stream as Disjoint Intervals

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1] [1,

915. Partition Array into Disjoint Intervals

问题：给定数组，切分为left和right，使得left的所有元素<=right的所有元素，返回left的长度 Example 1: Input: [5,0,3,8,6] Output: 3 Explanation: left = [5,0,3], right = [8,6] Example 2: Input: [1,1,1,0,6,12] Output: 4 Explanation: left = [1,1,1,0], right = [6,12] No

Codeforces 1025F Disjoint Triangles (计算几何)

题目链接 https://codeforces.com/contest/1025/problem/F 题解一道挺有意思的计算几何题 qwq 关键在于注意到任何一对不相交的三角形之间，一定有 \(2\) 条内公切线，而一对相交的三角形之间有 \(0\) 条。于是枚举两个点，求一下这两个点的连线两侧分别有多少点，就可以求出有多少对三

并查集

并查集百度定义并查集是一种树型的数据结构，用于处理一些不相交集合（Disjoint Sets）的合并及查询问题。常常在使用中以森林来表示。结合时事更让人理解其中A地爆发肺炎

D - Disjoint Set of Common Divisors

https://atcoder.jp/contests/abc142/tasks/abc142_d 题意求满足互素条件下的A和B的因子最多有几个思路：分解gcd（A,B）的质因子，再加上1； #include <iostream>#include<algorithm>#include<string>using namespace std;const int maxn =1e5+10;long long gcd(long long x,long lo