首页 > TAG信息列表 > DeserializeObject

wpf 中的 repeater ------- ItemsControl

<ItemsControl ItemsSource="{Binding Path=imageNames}" Padding="10"> <ItemsControl.ItemTemplate> <DataTemplate>

没有key的json怎么取value

如下一段json： [{ "id": "01", "text": "一" }, { "id": "02", "text": "二" }] 解析用的是：JObject jsonF = (JObject)JsonConvert.DeserializeObject(jsonS) 这句代码，然后取value怎么取？ 【如果在[前面加上{"resu

asp.net mvc post 接受 传输过来的json数据 并序列化为dynamic 方便访问 一句代码

[HttpPost]public ActionResult Login(){ var form = JsonConvert.DeserializeObject<dynamic>(new StreamReader(Request.InputStream).ReadToEnd()); string username = form.username; string password = form.password; ....}x 1[HttpPost]2public Acti

Newtonsoft.Json使用

1.将json字符串解析成指定对象 string guiddata ="带解析的数据";//序列化数据GuidResult model = JsonConvert.DeserializeObject<GuidResult>(guiddata);   1 public class GuidResult2 {3 public GuidData data { get; set; }4 public bool success { get;

JsonConvert

///"{'jsonParam' : " + jsonText + "}" /* Dictionary<string, object> tmp = (Dictionary<string, object>)jsonParam; Employee ee = JsonConvert.DeserializeObject<Employee>(JsonConvert.Ser