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Python基础(二)-列表

列表 列表数据类型 “列表”是一个值,它包含多个字构成的序列。属于“列表值”指的是列表本身(它作为一个值,可以保存在变量中,或传递给函数,像所有其他值一样),而不是指列表值之内的那些值。 列表用左方括号开始,右方括号结束,即[]。列表中的值也成为“表项”。表项用逗号分隔。 ['cat',

【AGC056E】Cheese(DP)

Cheese 题目链接:AGC056E 题目大意 给你一个环,边上有老鼠,然后会进行 n-1 次操作: 每次选一个一个点放一个奶酪(每个点的概率给出),然后奶酪会顺时针跑,每到一个老鼠就判定是否被吃,被吃了就那个老鼠和这个奶酪都没了。 要你求最后剩下某个老鼠的概率。 思路 首先做这个东西有一个很重要的

统信UOS(ubuntu20.4)+B525 linux上使用摄像头

1,linux不识别摄像头 解决:如图 切换usb连接状态   解决结果:如图 摄像头获取状态   2,运行报错,错误log如下,并图像卡住。 (cheese:2633): cheese-WARNING **: A lot of buffers are being dropped.: gstbasesink.c(2854): gst_base_sink_is_too_late (): /GstCameraBin:camera

AGC056E Cheese 题解

link Solution 我们可以发现的是,奶酪的投放顺序不会影响我们老鼠能否吃到的概率。考虑破环成链(编号 \(0\) ~ \(n-1\)),然后我们可以设 \(c_i\) 表示第 \(i\) 段的奶酪经过次数,\(x\) 为越过整圈的次数,那么对于第 \(n-1\) 只老鼠,它吃不到的概率就是: \[2^{-x}\prod_{i=0}^{n-2} (1-2^{-

LaTeX使用BibTex管理引用文献

我的个人网站 http://www.cheese.ren/ 博客来源 http://www.cheese.ren/blog/blog/346 欢迎交换友链 :-) 在LaTeX文档目录内创建一个documents.bib文件,文件名可自定义。 在google scholar上找一篇文献,点击左下方引号图案获取引用: 我们点击BibTex获取引用: 随后将此段复制

HDU - 1078 FatMouse and Cheese

FatMouse and Cheese HDU - 1078 AYIT-2021 609暑假集训第一周下 记忆化搜索和背包 FatMouse has stored some cheese in a city. The city can be considered as a square grid of dimension n: each grid location is labelled (p,q) where 0 <= p < n and 0 <= q < n. At

FatMouse and Cheese --- 记忆化搜索

** FatMouse and Cheese ** 题目: FatMouse has stored some cheese in a city. The city can be considered as a square grid of dimension n: each grid location is labelled (p,q) where 0 <= p < n and 0 <= q < n. At each grid location Fatmouse has hid b

log4js基本使用

const log4js = require("log4js"); log4js.configure({ appenders: { cheese: { type: "file", filename: "cheese.log" } }, categories: { default: { appenders: ["cheese"], level: "info" } } }); const logge

Fatmouse and cheese

Problem Description FatMouse has stored some cheese in a city. The city can be considered as a square grid of dimension n: each grid location is labelled (p,q) where 0 <= p < n and 0 <= q < n. At each grid location Fatmouse has hid between 0 a

windows 下可执行node处理 对比记录

mac、 linux #!/usr/bin/env node const { program } = require('commander'); program .description('An application for pizza ordering') .option('-p, --peppers', 'Add peppers') .option('-c, --cheese <type&

HDU - 1078 FatMouse and Cheese

传送门 记忆化搜索 #include<iostream> #include<algorithm> #include<map> #include<set> #include<vector> #include<utility> #include<list> #include<deque> #include<queue> #include<stack> #include<string&g

常用内置模块-06学习

常用内置模块学习 先安装log4js npm install log4js -D 1.url // 常用内置模块 const log4js = require('log4js') log4js.configure({ appenders: { cheese: { type: 'file', filename: 'cheese.log' } }, categories: { default: { appenders: ['che

Python基础教程:copy()和deepcopy()

在处理列表和字典时,尽管传递引用常常是最方便的方法,但如果函数修改了传入的列表或字典,你可能不希望这些变动影响原来的列表或字典。要做到这一点,Python提供了名为copy的模块,其中包含copy()和deepcopy()函数。 第一个函数copy.copy(),可以用来复制列表或字典这样的可变值,而不是

FatMouse and Cheese HDU - 1078

原题链接 考察:记忆化搜索 错误思路:        将f[i][j]定义为达到此点的最大分数,结果是TLE. 正确思路:        和滑雪那道题一样,要将f[i][j]定义为从mp[i][j]出发的最大分数. 1 #include <iostream> 2 #include <algorithm> 3 #include <cstdio> 4 #include <cstri

AOJ 0558 Cheese

#include<iostream> #include<queue> #include<cmath> #include<cstring> using namespace std; typedef struct node { int x,y,d; node(int a, int b, int c){ x = a, y = b, d = c;} }node; int h, w, n; char map[1000][1000]; int ans

洛谷P2979 cheese towers 完全背包

因为背包忘了不少,所以最近在找usaco上的一些难度不大的背包题练习 题目链接:https://www.luogu.com.cn/problem/P2979 题意:有n种奶酪,每种有高度h和价值v,高度>=k称为大奶酪。大的压在上面,下面所有奶酪的高度会变为原来的4/5(只考虑最上面的一个大奶酪的效果,意思是下面的不会重复被压

FatMouse and Cheese HDU - 1078 dp

#include<cstdio> #include<iostream> #include<cstring> using namespace std; int n,k; int dir[4][2]={{-1,0},{1,0},{0,-1},{0,1}}; int dp[101][101],mp[101][101]; bool check(int x,int y) { if(x<1||x>n||y<1||y>n) return

copy模块的copy和deepcopy函数

>>> import copy >>> spam = [1, 2, 3] >>> cheese = copy.copy(spam) >>> cheese[1] = 42 >>> cheese [1, 42, 3] >>> spam [1, 2, 3] >>> kat = copy.deepcopy(spam) >>> kat[2] = 400 >>&

类、对象

1 python中的任何一条数据都是对象,每个对象都由3部分组成:标识、类型和值。 对象的标识代表该对象在内存中的存储位置 不可更改,对象的类型表明它可以拥有的数据和值的类型。在对象中,可变类型的值可以更改,不可变类型的值不能更改 2 类允许定义一组对象,并将它们封装到一个方便的空间

CAB202 Assignment 1

CAB202 Assignment 1, Semester 2 2019Assessment Weight: 30%ContextYou are tasked with bringing to life the classic characters of Tom and Jerry in a terminal basedgame. Tom is a cat with the simple agenda of catching the mouse, Jerry, running rampant in his

python del 和弱引用

一:del python 中del语句是删除名称,不是对象,具体看如下可视化: d = [1,2,3] d2 = d del d print(d2) 第一步: 第二步: 第三步:   当删除的变量保存的是对象的对吼一个引用或者无法得到对象时,del会导致对象被当作垃圾回收。 =================================================

FatMouse and Cheese

FatMouse and Cheese (记忆化) FatMouse has stored some cheese in a city. The city can be considered as a square grid of dimension n: each grid location is labelled (p,q) where 0 <= p < n and 0 <= q < n. At each grid location Fatmouse has hid betwe

FatMouse and Cheese

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=1107   FatMouse has stored some cheese in a city. The city can be considered as a square grid of dimension n: each grid location is labelled (p,q) where 0 <= p < n and 0 <= q < n. A

HDU - 1078 FatMouse and Cheese

再谈记忆化搜索 题目描述: FatMouse has stored some cheese in a city. The city can be considered as a square grid of dimension n: each grid location is labelled (p,q) where 0 <= p < n and 0 <= q < n. At each grid location Fatmouse has hid between 0 and 100

Python_list(列表)

list """sep""" print('hh', 'xx', 'kk', sep=';') # hh;xx;kk """del""" spam = ['cat', 'bat', 'rat', 'elephant'] del s