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交替方向乘子法（Alternating Direction Multiplier Method，ADMM）
交替方向乘子法（Alternating Direction Multiplier Method，ADMM）是一种求解具有可分结构的凸优化问题的重要方法，其最早由Gabay和Mercier于1967年提出。ADMM是结合对偶上升法的可分离特性以及ALM松弛收敛条件，所形成的一种改进方法[5]，该算法在大规模数据分析处理领域因处理速度快，收敛性1343C - Alternating Subsequence
链接： https://codeforces.com/problemset/problem/1343/C 题意： 子序列：原序列删减不改变顺序 要求找出最大长度，正负交叉，【正负正负…】，【负正负正…】 求最大长度的子序列的和的最大值 解： 思维题和阅读题（读题重点） 题目要求的最大长度是固定条件，所有能取都要取 只要在每个正负[LeetCode] 1129. Shortest Path with Alternating Colors
Consider a directed graph, with nodes labelled 0, 1, ..., n-1. In this graph, each edge is either red or blue, and there could be self-edges or parallel edges. Each [i, j] in red_edges denotes a red directed edge from node i to node j. Similarly,交替方向乘子法（Alternating Direction Method of Multipliers）
交替方向乘子法（Alternating Direction Method of Multipliers） 作者：凯鲁嘎吉 - 博客园 http://www.cnblogs.com/kailugaji/ 1. 交替方向乘子法简介——Alternating Direction Method of Multipliers ADMM 最早分别由 Glowinski & Marrocco 及 Gabay & Mercier 于 1975 年和CodeForces - 960E Alternating Tree
题意： 给定一棵有 nnn 个结点的树，边权均为 111，结点带点权 ViV_iVi，一条路径 (v1,v2,...,vm)(v_1,v_2,...,v_m)(v1,v2,...,vm) 的权值定义为 ∑i=1m(−1)(i+1)Vvi\sum\limits_{i = 1}^{m}(-1)^{(i + 1)}V_{v_i}i=1∑m(−1)(i+1)Vvi，求所有路径权值总和。(n≤2×10#leetCode刷题纪实 Day31
https://leetcode-cn.com/problems/binary-number-with-alternating-bits/ 给定一个正整数，检查他是否为交替位二进制数：换句话说，就是他的二进制数相邻的两个位数永不相等。 示例 1: 输入: 5输出: True解释:5的二进制数是: 101示例 2: 输入: 7输出: False解释:7的二进制数是: 111示【leetcode】1129. Shortest Path with Alternating Colors
题目如下： Consider a directed graph, with nodes labelled 0, 1, ..., n-1. In this graph, each edge is either red or blue, and there could be self-edges or parallel edges. Each [i, j] in red_edges denotes a red directed edge from node i to node j. SPHP循环中的交替颜色行
如何在我的php循环中有一个交替的颜色行？ $num = mysql_num_rows($qPhysician); $i=0; while($i < $num) { echo "<tr>"; echo "<td>" . mysql_result($qPhysician,$i,"lastName") . "</td>"; echo "<t[Swift]LeetCode693. 交替位二进制数 | Binary Number with Alternating Bits
Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values. Example 1: Input: 5Output: TrueExplanation:The binary representation of 5 is: 101 Example 2: Input: 7Output: FalseExplanationLeetCode 693 Binary Number with Alternating Bits 解题报告
题目要求 Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values. 题目分析及思路 给定一个正整数，判断它的二进制形式是否是01交替出现。如果是则返回True，否则返回False。可以先获得该数的二进制形式