首页 > TAG信息列表 > 3Sum
LeetCode 3Sum 双指针
Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j, i != k, and j != k, and nums[i] + nums[j] + nums[k] == 0. Notice that the solution set must not contain duplicate triplets. Solution 我们需要输出方案,不在乎下标,【题解】CF1698C 3SUM Closure
【题解】CF1698C 3SUM Closure 链接 题意简述 有一个长度为 \(n\) 的序列 \(a\) 。如果对于 $\forall i , j , k\in[1,n] $ ,\(\exist a_i+a_j+a_k \in a\) ,那么称这个序列为 "3SUM-closed" 给出序列 \(a\) ,问这个序列是否为 "3SUM-closed" 题目分析 我是通过不断寻找反例来逐渐缩LeetCode 0015 3Sum
原题传送门 1. 题目描述 2. Solution 1 1、思路分析 3重循环,实现略 3. Solution 2 1、思路分析 固定一个数,另外两个数用双指针定位。 2、代码实现 package Q0099.Q0015ThreeSum; import java.util.Arrays; import java.util.LinkedList; import java.util.List; /* 方法一Leetcode 15. 三数之和 3Sum - Python 双指针法
class Solution: def threeSum(self, nums: List[int]) -> List[List[int]]: result = [] #将数组从小到大排序,便于双指针法的实施 nums.sort() for i in range(len(nums)): if i == 0 or nums[i] != nums[i-1]: #第一个元素 或 跟前一LeetCode 15.三数之和 双指针思路
https://leetcode-cn.com/problems/3sum/LeetCode-15. 3Sum [C++]
LeetCode-15. 3Sumhttps://leetcode.com/problems/3sum/ 题目描述 Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c= 0? Find all unique triplets in the array which gives the sum of zero. Note: The solutionLeetCode图解 3Sum & Array类型问题
LeetCode图解 3Sum & Array类型问题 目录LeetCode图解 3Sum & Array类型问题1.问题描述2.测试用例3.提示4.解题思路一、暴力二、hash三、双指针5.图解(双指针) 1.问题描述 给你一个包含 n 个整数的数组 nums,判断 nums 中是否存在三个元素 a,b,c ,使得 a + b + c = 0 ?请你找出所有和为 0《中英双解》leetCode 3Sum(三数之和)
Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j, i != k, and j != k, and nums[i] + nums[j] + nums[k] == 0. Notice that the solution set must not contain duplicate triplets. 给你一个包含 n 个整数的数组[LeetCode] 259. 3Sum Smaller tag: Two pointers
Given an array of n integers nums and an integer target, find the number of index triplets i, j, k with 0 <= i < j < k < n that satisfy the condition nums[i] + nums[j] + nums[k] < target. Example 1: Input: nums = [-2,0,1,3], target = 2 OuFarmer John Solves 3SUM
F a r m e r J o[LeetCode] 15. 3Sum(三数之和)
Difficulty: Medium Related Topics: Array, Two Pointers Link: https://leetcode.com/problems/3sum/ Description Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in theLeetcode 3Sum
1 class Solution { 2 public List<List<Integer>> threeSum(int[] nums) { 3 if (nums == null || nums.length <= 2) return new ArrayList(); 4 5 Arrays.sort(nums); 6 7 List<List<Integer&gLC15-3Sum
https://leetcode.com/problems/3sum/ 给一个数组,要求返回其中所有各不相同的三元组,每个三元组中的三个数相加和为0 O(N2)解法: 本题是Two Sum的进阶版,枚举数组中的数nums[i],然后用O(N)的复杂度在剩下的数中使用Two Sum找到和为-nums[i]的不同组合 先对nums数组进行快速排序(从小3Sum
Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero. Note: The solution set must not contain duplicate triplets. Example: Given array nums = [-1,刷题15. 3Sum
一、题目说明 题目非常简洁15. 3Sum,读懂题目后,理解不难。 但 实话说,我们提交代码后,Time Limit Exceeded,最主要的是给了非常长的测试用例,我本地运行后87秒,确实时间非常长。 二、我的解答及问题 下面是我的解答代码,通过该例子可以学习如何写测试代码: #include<iostream> #include<ve[LC] 259. 3Sum Smaller
Given an array of n integers nums and a target, find the number of index triplets i, j, k with 0 <= i < j < k < n that satisfy the condition nums[i] + nums[j] + nums[k] < target. Example: Input: nums = [-2,0,1,3], and target = 2 Output: 2LeetCode 923. 3Sum With Multiplicity
原题链接在这里:https://leetcode.com/problems/3sum-with-multiplicity/ 题目: Given an integer array A, and an integer target, return the number of tuples i, j, k such that i < j < k and A[i] + A[j] + A[k] == target. As the answer can be very large, retur16. 3Sum Closest (M)
3Sum Closest (M) Given an array nums of n integers and an integer target, find three integers in nums such that the sum is closest to target. Return the sum of the three integers. You may assume that each input would have exactly one solution. Example:Leetcode 15: 3Sum
class Solution: def threeSum(self, nums: List[int]) -> List[List[int]]: result=[] n = len(nums) nums.sort() for i in range(n-2): if i>0 and nums[i]==nums[i-1]: continue l, rLeetcode 16: 3Sum Closest
class Solution: def threeSumClosest(self, nums: List[int], target: int) -> int: res=0 temp=float('inf') nums.sort() n=len(nums) #[-3, 0, 1, 2] for i in range(n-2): l, r= i+1, n-13Sum
题目描述: Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero. Note: Elements in a triplet (a,b,c) must be in non-descending order. (ie,3Sum Closest
题目描述: Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution. For example, given arrayleetcode 15. 3Sum
Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero. Note: The solution set must not contain duplicate triplets. Example: Given array nums = [-1LeetCode开心刷题第八天——15 3sum
15 3sum this question is a complex problem to me because it's hard to detailed classification. Special Usage: vector<vector<int>> this container is equivalent to a two-dimensional array.if we use vector<int>,we can only put one vari16. 3Sum Closest[M]最接近的三数之和
题目 Given an array nums of n integers and an integer target, find three integers in nums such that the sum is closest to target. Return the sum of the three integers. You may assume that each input would have exactly one solution. Example: Given array nu