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2192:Zipper DP+DFS
2192:Zipper #include <bits/stdc++.h> using namespace std; //0、状态是什么？怎么表示 //1、分解成子问题 //2、无后效性，一种状态A只与另一种状态B的值有关，与状态B的到达方式无关 string s1,s2,s3;//用string 声明字符串就不用考虑字符串长度 int len1,len2,len3; int dZookeeper安装与调优部署参考文档(Linux)
1. 安装环境准备 1.1 主机环境准备 1.1.1. 关闭selinux sed -i 's/SELINUX=enforcing/SELINUX=disabled/g' /etc/selinux/config setenforce 0 1.1.2. 软件下载 apache-zookeeper-3.6.1-bin.tar.gz：下载地址 1.1.3. 部署规划 软件安装路径 /usr/local/zookeeper端口规划 2192 1.1.4.【OpenJ_Bailian - 2192】Zipper
Zipper Descriptions: Given three strings, you are to determine whether the third string can be formed by combining the characters in the first two strings. The first two strings can be mixed arbitrarily, but each must stay in its original order. For examZipper OpenJ_Bailian - 2192 (DP最长公共子串)
Given three strings, you are to determine whether the third string can be formed by combining the characters in the first two strings. The first two strings can be mixed arbitrarily, but each must stay in its original order. For example, consider formin