输入10个整数，将其中最小的数与第一个数对换，把最大的数与最后一个数对换。写三个函数。。。用指针做题

#include<iostream>
using namespace std;
int main()
{
	void input(int* number);
	void max_min(int* number);
	void output(int* number);
	int num[10];
	input(num);
	max_min(num);
	output(num);

	return 0;
}
void input(int* number)
{
	cout << "pleas enter 10 number:";
	for (int i = 0; i < 10; i++) {
		cin >> number[i];
	}
}
void max_min(int* number)
{
	int* max, * min, * p;
	max = min =  number;
	int temp;
	for (p=number; p<number+10;p++) {
		if (*p > *max) max = p;
	}
	temp = *max; *max = number[9]; number[9] = temp;
	for (p = number; p < number + 10; p++) {
		if (*p < *min) min = p;
	}
	temp = *min; *min = number[0]; number[0] = temp;
}
void output(int* number)
{
	for (int i = 0; i < 10; i++) {
		cout << number[i] << " ";
	}
}

标签：10,temp,min,int,max,void,对换,number,指针
来源： https://blog.csdn.net/weixin_58346553/article/details/117375621