PTA乙级1012

注意点 第二个交错求和要用个数来记录是否有数字满足 而不是判断是否为0 否则有一个点不过

AC代码

#include<iostream>

using namespace std;


int a1,a2,a3,a4,a5;
int fl=1;
int maxx=-1;
int i,j,k;

int main()
{
	int n;
	cin>>n;
	int x;
	while(n--)
	{
		cin>>x;
		if(x%5==0)
		{
			if(x%2==0)
			a1+=x;//he
		}
		else if(x%5==1)
		{
			a2+=x*fl;
			fl*=-1;//jiaocuo
			k++;
		}
		else if(x%5==2)
		{
			i++;//geshu
		 }
		 else if(x%5==3)
		 {
		 	a4+=x;//pingjunshu
		 	j++;
		  }
		  else if(x%5==4)
		  {
		  	if(x>maxx)
		  	maxx=x;//zuidazhi
		   } 
		   
	}
	
	if(a1==0)
	printf("N ");
	else
	printf("%d ",a1);
	
	if(k==0)
	printf("N ");
	else
	printf("%d ",a2);
	
	if(i==0)
	printf("N ");
	else
	printf("%d ",i);
	
	if(j==0)
	printf("N ");
    else
	printf("%.1lf ",(double)a4/j);
	
	if(maxx==-1)
	printf("N\n");
	else
	printf("%d\n",maxx);
 } 

标签：maxx,int,PTA,else,a1,乙级,printf,x%,1012
来源： https://blog.csdn.net/m0_51305283/article/details/116947536