1058: 求解不等式

#include<stdio.h>
int main()
{
int n,m,i;
double sum,x;
scanf("%d",&n);
x = 1;
sum = 0;

for(i=1;;i++)
{
    x *= i;
    sum += x;

    if(sum >= n)
        {
            printf("m<=%d\n",i-1);
            break;
        }
}
return 0;

}

1. List item

标签：不等式,求解,1058,double,sum,List,int,main
来源： https://blog.csdn.net/m0_52433518/article/details/113068374