PAT A1080(部分测试点无法通过)
作者:互联网
#include<iostream>
#include<algorithm>
#include<vector>
using namespace std;
const int maxn = 40010;
struct Stu{
int id, ge, gi, total, rankPos;
int pre[6];
}stu[maxn];
vector<int> school;
vector<int> admit[100];
bool cmp(Stu a, Stu b) {
if(a.total != b.total) return a.total > b.total;
else if(a.ge != b.ge) return a.ge > b.ge;
}
int main() {
int n, m, k;
cin >> n >> m >> k;
for(int i=0;i<m;i++) {
int temp;
cin >> temp;
school.push_back(temp);
}
for(int i=0; i<n; i++) {
stu[i].id = i;
cin >> stu[i].ge >> stu[i].gi;
stu[i].total = stu[i].ge + stu[i].gi;
for(int j=0; j<k; j++) {
cin >> stu[i].pre[j];
}
}
sort(stu, stu+n, cmp);
stu[0].rankPos = 1;
for(int i=1;i<n;i++) {
stu[i].rankPos = i+1;
if(stu[i].ge == stu[i-1].ge && stu[i].total == stu[i-1].total) {
stu[i].rankPos = stu[i-1].rankPos;
}
}
for(int i=0; i<n; i++) {
for(int j=0; j<k; j++) {
if(school[stu[i].pre[j]] > 0) {
admit[stu[i].pre[j]].push_back(stu[i].id);
school[stu[i].pre[j]] --;
break;
} else {
int lastId, admitSize;
admitSize = admit[stu[i].pre[j]].size();
if(admitSize) {
lastId = admit[stu[i].pre[j]][admitSize-1];
if(stu[i].rankPos == stu[lastId].rankPos) {
admit[stu[i].pre[j]].push_back(stu[i].id);
school[stu[i].pre[j]]--;
break;
}
}
}
}
}
for(int i=0; i<m; i++) {
if(admit[i].size()) {
sort(admit[i].begin(), admit[i].end());
for(int j=0; j < admit[i].size(); j++) {
if(j) printf(" ");
printf("%d", admit[i][j]);
}
}
if(i!=m-1) printf("\n");
}
return 0;
}
测试点1,2,4不过???????
标签:pre,PAT,测试点,int,A1080,ge,stu,admit,total 来源: https://blog.csdn.net/qq_29948297/article/details/112626724