LeetCode83. 删除排序链表中的重复元素

☆☆解法

class Solution {
    public ListNode deleteDuplicates(ListNode head) {
        if (head == null || head.next == null) return head;
        ListNode cur = head;
        while (cur != null && cur.next != null) {
            if (cur.val == cur.next.val) {
                cur.next = cur.next.next;
            }else {
                cur = cur.next;
            }
        }

        return head;
    }
}

标签：head,null,ListNode,cur,val,LeetCode83,next,链表,排序
来源： https://www.cnblogs.com/HuangYJ/p/14128994.html