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实现Runnable接口(龟兔赛跑完整代码)

作者:互联网

下面是一个龟兔赛跑的例子:

public class Race implements Runnable {
    //胜利者
    private  static String winner;

    @Override
    public void run() {
        for (int i = 0; i <= 100; i++) {
            //模拟兔子休息
            if (Thread.currentThread().getName().equals("兔子") && i%10==0){
                try {
                    Thread.sleep(1);
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }

            //判断比赛是否结束
            boolean flag = gameOver(i);
            //如果比赛结束,终止程序
            if (flag) {
                break;
            }
            System.out.println(Thread.currentThread().getName() + "-->跑了" + i + "步");
        }
    }
    //判断是否完成比赛
    private boolean gameOver(int steps){
        if (winner != null){
            return true;
        }{
            if (steps >= 100){
                winner = Thread.currentThread().getName();
                System.out.println("winner is"+winner);
                return true;
            }
        }
        return false;
    }

    public static void main(String[] args) {
        Race race = new Race();
        new Thread(race,"兔子").start();
        new Thread(race,"乌龟").start();
    }
}

标签:赛跑,龟兔,return,Thread,winner,start,Runnable,race,public
来源: https://www.cnblogs.com/hellowen/p/12875758.html