HDU4091:Zombie’s Treasure Chest (分类-数学)
作者:互联网
题意:给两种宝石,体积S1,S2,价值V1,V2,背包容量n,求最大收益。
#include<bits/stdc++.h> #define s first #define e second #define rep(i,a,b) for(ll i=a;i<=b;i++) #define rep2(i,a,b) for(int i=a;i>=b;i--) #define ll long long using namespace std; int main() { int T,C=0; ll S,S1,V1,S2,V2,ans; scanf("%d",&T); while(T--){ scanf("%lld%lld%lld%lld%lld",&S,&S1,&V1,&S2,&V2); printf("Case #%d: ",++C); ans=0; if(S1<=S2&&V1>=V2) ans=max(ans,(S/S1)*V1); if(S2<=S1&&V2>=V1) ans=max(ans,(S/S2)*V2); if(S1*S1>=S){ rep(i,0,S/S1) ans=max(ans,V1*i+(S-S1*i)/S2*V2); } if(S2*S2>=S){ rep(i,0,S/S2) ans=max(ans,V2*i+(S-S2*i)/S1*V1); } if(S1*S1<S&&S2*S2<S){ rep(i,0,max(S1,S2)){ if(S>=S1*i) ans=max(ans,V1*i+(S-S1*i)/S2*V2); if(S>=S2*i) ans=max(ans,V2*i+(S-S2*i)/S1*V1); } } printf("%lld\n",ans); } return 0; }
标签:max,HDU4091,S2,S1,Treasure,Zombie,V1,V2,ans 来源: https://www.cnblogs.com/hua-dong/p/11181826.html