一、基础知识夯实

1.首先是我们需要懂得几点是在java中的集中运算

直接看代码吧

public class IntToBinary {
    public static void main(String[] args) throws UnsupportedEncodingException {

        int data = 4;
        System.out.println("the 4 is "+Integer.toBinaryString(data));

        //位与  &(1&1=1 1&0=0 0&0=0)
        System.out.println("the 4 is "+Integer.toBinaryString(4));
        System.out.println("the 6 is "+Integer.toBinaryString(6));
        System.out.println("the 4&6 is "+Integer.toBinaryString(4&6));
        //位或 | (1|1=1 1|0=1 0|0=0)
        System.out.println("the 4|6 is "+Integer.toBinaryString(4|6));
        //位非~（~1=0  ~0=1）
        System.out.println("the ~4 is "+Integer.toBinaryString(~4));
        //位异或 ^ (1^1=0 1^0=1 0^0=0)(有相同的就是 1 )
        System.out.println("the 4^6 is "+Integer.toBinaryString(4^6));

        // <<有符号左移 >>有符号的右移  >>>无符号右移
        System.out.println("the 1 << 4 is "+Integer.toBinaryString(4 << 1));
        System.out.println("the 1 >>> 4 is "+Integer.toBinaryString(4 >>> 1));
        //取模的操作 a % (2^n) 等价于 a&(2^n-1)
        System.out.println("the 345 % 16 is "+(345%16)+ " or "+(345&(16-1)));

    }
}

View Code

 

标签：容器,第一,16,System,并发,toBinaryString,println,Integer,out
来源： https://www.cnblogs.com/lys-lyy/p/11072796.html