channel
作者:互联网
channel有缓冲与无缓冲同步问题
package main
import (
"fmt"
"time"
)
func main() {
c := make(chan int, 3) //带有缓冲的channel
fmt.Println("len(c) = ", len(c), ", cap(c)", cap(c))
go func() {
defer fmt.Println("子go程结束")
for i := 0; i < 4; i++ {
c <- i
fmt.Println("子go程正在运行, 发送的元素=", i, " len(c)=", len(c), ", cap(c)=", cap(c))
}
}()
time.Sleep(2 * time.Second)
for i := 0; i < 4; i++ {
num := <-c //从c中接收数据,并赋值给num
fmt.Println("num = ", num)
}
fmt.Println("main 结束")
}
关闭channel
package main
import "fmt"
func main() {
c := make(chan int)
go func() {
for i := 0; i < 5; i++ {
c <- i
//close可以关闭一个channel
close(c)
}
}()
for {
//ok如果为true表示channel没有关闭,如果为false表示channel已经关闭
if data, ok := <-c; ok {
fmt.Println(data)
} else {
break
}
}
fmt.Println("Main Finished..")
}
标签:缓冲,fmt,func,go,main,channel 来源: https://www.cnblogs.com/suehoo/p/16638896.html