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LeetCode 169 Majority Element

作者:互联网

Given an array nums of size n, return the majority element.

The majority element is the element that appears more than ⌊n / 2⌋ times. You may assume that the majority element always exists in the array.

Solution

利用投票法即可:遇到相同的元素,就将计数器加一;否则减一,如果为0,则赋值给下一个元素

点击查看代码
class Solution {
public:
    int majorityElement(vector<int>& nums) {
        int n = nums.size();
        if(n==1)return nums[0];
        int ans=nums[0];
        int cnt=1;
        for(int i=1;i<n;i++){
            if(nums[i]==ans)cnt++;
            else{
                cnt--;
                if(cnt==0)ans=nums[i],cnt=1;
            }
        }
        return ans;
    }
};

标签:majority,nums,int,element,Majority,array,Element,LeetCode,size
来源: https://www.cnblogs.com/xinyu04/p/16590250.html