Codeforces Round #810 (Div. 2)

比赛链接

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A. Perfect Permutation

原题链接

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You are given a positive integer n.

The weight of a permutation p1,p2,…,pn is the number of indices 1≤i≤n such that i divides pi. Find a permutation p1,p2,…,pn with the minimum possible weight (among all permutations of length n).

A permutation is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2,3,1,5,4] is a permutation, but [1,2,2] is not a permutation (2 appears twice in the array) and [1,3,4] is also not a permutation (n=3 but there is 4 in the array).

Input

Each test contains multiple test cases. The first line contains the number of test cases t (1≤t≤10^4). The description of the test cases follows.

The only line of each test case contains a single integer n (1≤n≤10^5) — the length of permutation.

It is guaranteed that the sum of n over all test cases does not exceed 10^5.

Output

For each test case, print a line containing n integers p1,p2,…,pn so that the permutation p has the minimum possible weight.

If there are several possible answers, you can print any of them.

Example

input

2
1
4

outputCopy

1
2 1 4 3

题目大意

构造一个含1~n的长度为n的数列，满足 p[i]/i有最小值。
因此只需要将数组向左移动一位就行。

代码

#include <iostream>
#include <cstring>
#include <cstdio>
#include <cmath>
#include <algorithm>

using namespace std;

void solve()
{
	int n;
	cin >> n;
	
	for(int i = 2;i <= n;i ++)
		cout << i << " ";
	cout << 1 << endl;
	
}

int main()
{
	
	int T;
	cin >> T;
	
	while( T-- )
		solve();
	
	return 0;
}

标签：p2,line,Codeforces,test,permutation,810,Div,include,cases
来源： https://www.cnblogs.com/heystar/p/16533195.html