字符串冒泡排序方法
作者:互联网
def str_bubble(s1): if s1: if isinstance(s1[0], int): n = len(s1) s1 = list(map(lambda x: str(x), s1)) else: pass for i in range(n): for j in range(i + 1, n): if int(s1[i] + s1[j]) > int(s1[j] + s1[i]): pass else: s1[i], s1[j] = s1[j], s1[i] return s1
标签:int,s1,冒泡排序,else,range,str,pass,字符串,方法 来源: https://www.cnblogs.com/icxk/p/16437036.html