HDU 2176 取(m堆)石子游戏

\(HDU2176\)

先取者负输出\(No\).先取者胜输出\(Yes\),然后输出先取者第\(1\)次取子的所有方法.如果从有\(a\)个石子的堆中取若干个后剩下\(b\)个后会胜就输出\(a\) \(b\)

#include <bits/stdc++.h>
using namespace std;
const int N = 200010;
int a[N];

int main() {
    int n;
    while (~scanf("%d", &n) && n) {
        int x = 0;
        for (int i = 0; i < n; i++) {
            scanf("%d", &a[i]);
            x = x ^ a[i];
        }
        if (!x)
            puts("No");
        else {
            puts("Yes");
            for (int i = 0; i < n; i++) {
                int res = a[i] ^ x;
                //找到了证明中提到的: a_i ,此堆的数量最高位第k位，数值为1
                //拿走：a[i]- (a[i]^x)
                //剩下：a[i]^x = res个
                if (res < a[i])
                    printf("%d %d\n", a[i], res);
            }
        }
    }
    return 0;
}

标签：输出,HDU,puts,No,int,res,石子,先取,2176
来源： https://www.cnblogs.com/littlehb/p/16403990.html