稀疏数组
作者:互联网
稀疏数组
package base.array;
public class ArrayDemo8 {
public static void main(String[] args) {
//编写五子棋游戏
//1.创建一个二维数组11*11 0代表没有棋子 1黑棋 2白棋
int[][] array1 = new int[11][11];
array1[1][2] = 1;
array1[2][3] = 2;
//输出原始的数组
System.out.println("输出原始的数组");
for (int[] ints : array1) {
for (int anInt : ints) {
System.out.print(anInt + "\t");
}
System.out.println();
}
System.out.println("==========================");
//转换为稀疏数组
//获取有效值的个数
int sum = 0;
for (int i = 0; i < 11; i++) {
for (int j = 0; j < 11; j++) {
if (array1[i][j]!= 0) {
sum++;
}
}
}
System.out.println("有效值得个数:" + sum);
//创建一个稀疏数组的数组
int[][] array2 = new int[sum + 1][3];
array2[0][0] = 11;
array2[0][1] = 11;
array2[0][2] = sum;
//遍历二维数组,将非零的值,存放在稀疏数组中
int count = 0;
for (int i = 0; i < array1.length; i++) {
for (int j = 0; j < array1[i].length; j++) {
if (array1[i][j]!=0){
count++;
array2[count][0] = i;
array2[count][1] = j;
array2[count][2] = array1[i][j];
}
}
}
//输出稀疏数组
System.out.println("稀疏数组");
for (int i = 0; i < array2.length; i++) {
System.out.println(array2[i][0] + "\t"
+ array2[i][1] + "\t"
+ array2[i][2] + "\t");
}
System.out.println("==========================");
System.out.println("还原稀疏数组");
//1.读取稀疏数组
int[][] array3 = new int[array2[0][0]][array2[0][1]];
//2.给其中的元素还原他的值
for (int i = 1; i < array2.length; i++) {
array3[array2[i][0]][array2[i][1]] = array2[i][2];
}
//打印
System.out.println("输出还原的数组");
for (int[] ints : array3) {
for (int anInt : ints) {
System.out.print(anInt + "\t");
}
System.out.println();
}
}
}
标签:int,array2,System,稀疏,数组,println,out 来源: https://www.cnblogs.com/zenyangderensheng/p/16276923.html