[AcWing 851] spfa求最短路
作者:互联网
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#include<iostream>
#include<cstring>
#include<queue>
using namespace std;
const int N = 1e5 + 10;
int n, m;
int h[N], e[N], ne[N], w[N], idx;
int dist[N];
bool st[N];
void add(int a, int b, int c)
{
e[idx] = b;
w[idx] = c;
ne[idx] = h[a];
h[a] = idx++;
}
int spfa()
{
memset(dist, 0x3f, sizeof(dist));
dist[1] = 0;
queue<int> q;
q.push(1);
st[1] = true;
while (q.size()) {
int t = q.front();
q.pop();
st[t] = false;
for (int i = h[t]; i != -1; i = ne[i]) {
int j = e[i];
if (dist[j] > dist[t] + w[i]) {
dist[j] = dist[t] + w[i];
if (!st[j]) {
q.push(j);
st[j] = true;
}
}
}
}
return dist[n];
}
int main()
{
cin >> n >> m;
memset(h, -1, sizeof(h));
for (int i = 0; i < m; i ++) {
int a, b, c;
cin >> a >> b >> c;
add(a, b, c);
}
int t = spfa();
if (t == 0x3f3f3f3f) puts("impossible");
else cout << dist[n] << endl;
return 0;
}
- 在 dijkstra 的基础上进行优化,只有当队头节点出队时,队头的邻边才会进行更新;
- spfa 可以用来处理负权图的情况;
标签:dist,851,idx,int,ne,st,spfa,AcWing 来源: https://www.cnblogs.com/wKingYu/p/16241435.html