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稀疏数组

作者:互联网

public static void main(String[] args) {
//1.创建一个二维数组 11*11 0:没有旗子, 1:黑旗 2:白旗
int[][] array1 = new int [11] [11];
array1[1][2] = 1;
array1[2][3] = 1;
//输出原始的数组
System.out.print("输出原始的数组");

for (int[] ints : array1){
for (int anInt : ints){
System.out.println(anInt+"\t");
}
System.out.println();
}
System.out.println("=======================");
//转换为稀疏数组保存
//获取有效值的个数
int sum = 0;
for (int i = 0; i < 11; i++) {
for (int j = 0; j < 11; j++) {
if (array1[i][j]!=0){
sum++;
}
}
}
System.out.println("有效值的个数:"+sum);

//创建一个稀疏数组的数组
int[][] array2 = new int[sum+1][3];

array2[0][0] = 11;
array2[0][1] = 11;
array2[0][2] = sum;

//便利二维数组,将非零的值,存放稀疏数组中
int count=0;
for (int i = 0; i < array1.length; i++) {
for (int j = 0; j < array1[i].length; j++) {
if (array1[i][j]!=0){
count++;
array2[count][0] = j;
array2[count][1] = j;
array2[count][2] = array1[i][j];
}

}

}
//输出稀疏数组
System.out.println("稀疏数组");

for (int i = 0; i < array2.length; i++) {
System.out.println(array2[i][0]+"\t"
+array2[i][1]+"\t"
+array2[i][2]+"\t");
}

System.out.println("========================");
System.out.println("还原");
//1.读取稀疏数组
int[][] array3 = new int[array2[0][0]][array2[0][1]];
//2.给其中的元素还原它的值
for (int i = 1; i < array2.length; i++) {
array3[array2[i][0]][array2[i][1]] = array2[i][2];
}
//3.打印
System.out.println("输出还原的数组");
for (int[] ints : array3){
for (int anInt : ints){
System.out.print(anInt+"\t");
}
System.out.println();
}

标签:int,array2,System,稀疏,数组,println,out
来源: https://www.cnblogs.com/whm0826/p/15988710.html