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多线程模拟龟兔赛跑(兔子睡觉)

作者:互联网

public class race implements Runnable{
    //只能有一个赢家,所以这里winner是静态属性
    private static String winner;
    @Override
    public void run() {
        for (int i = 0; i < 100; i++) {
            if(Thread.currentThread().getName().equals("兔子")){
                try {
                    //当兔子在跑时,就让他休息1毫秒
                    Thread.sleep(1);
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
            boolean flag = gameOver(i);
            if(flag){
                break;
            }
            System.out.println(Thread.currentThread().getName()+"跑了"+i+"步");
          
        }
    }
    private boolean gameOver(int steps){
        if(winner!=null){
            return  true;
        }{
            if(steps>=99){
                winner = Thread.currentThread().getName();
                System.out.println(winner+"赢了!");
                return  true;
            }
        }return false;
    }

    public static void main(String[] args) {
        new Thread(new race(),"兔子").start();
        new Thread(new race(),"乌龟").start();

    }
}

标签:赛跑,龟兔,return,currentThread,Thread,getName,winner,new,多线程
来源: https://blog.csdn.net/Timooo_/article/details/121719992